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The representation theory of groups is a part of mathematics which examines how groups act on given structures.

Here the focus is in particular on operations of groups on vector spaces. Nevertheless, groups acting on other groups or on sets are also considered. For more details, please refer to the section on permutation representations.

Please note, that except for a few marked exceptions only finite groups will be considered in this article. We will also restrain to vector spaces over fields of characteristic zero. Because the theory of algebraically closed fields of characteristic zero is complete, a theory valid for a special algebraically closed field of characteristic zero is also valid for every other algebraically closed field of characteristic zero. Thus, without loss of generality, we can study vector spaces over $\mathbb {C} .$

Representation theory is used in many parts of mathematics, as well as in quantum chemistry and physics. Among other things it is used in algebra to examine the structure of groups. There are also applications in harmonic analysis and number theory. For example, representation theory is used in the modern approach to gain new results about automorphic forms.

Definition

Linear representations

Let $V$ be a $K-$vector space and $G$ a finite group. A linear representation of a finite group $G$ is a group homomorphism $\rho :G\to {\text{GL}}(V)={\text{Aut}}(V).$ That means, a linear representation is a map $\rho :G\to {\text{GL}}(V)$ which satisfies $\rho (st)=\rho (s)\rho (t)$ for all $s,t\in G.$ The vector space $V$ is called representation space of $G.$ Often the term representation of $G$ is also used for the representation space $V.$
The representation of a group in a module instead of a vector space is also called a linear representation.
We write $(\rho ,V_{\rho })$ for the representation $\rho :G\to {\text{GL}}(V_{\rho })$ of $G.$ Sometimes we only use $(\rho ,V),$ if it is clear to which representation the space $V$ belongs.
In this article we will restrain ourselves to the study of finite-dimensional representation spaces, except for the last chapter. As in most cases only a finite number of vectors in $V$ is of interest, it is sufficient to study the subrepresentation generated by these vectors. The representation space of this subrepresentation is then finite-dimensional.
The degree of a representation is the dimension ${\text{dim}}(V)=n$ of its representation space$V.$ Also the notation ${\text{dim}}(\rho )$ is sometimes used to denote the degree of a representation $\rho .$

Examples

A very elementary example is the trivial representation, which is given by $\rho (s)={\text{Id}}$ for all $s\in G.$
A representation of degree $1$ of a group $G$ is a homomorphism$\rho :G\to {\text{GL}}(\mathbb {C} )=\mathbb {C} ^{\times }$ in the multiplicative group $\mathbb {C} ^{\times }=\mathbb {C} \setminus \{0\}.$ As every element of $G$ is of finite order, the values of $\rho (s)$ are roots of unity.
Another nontrivial example:
Let $\rho :G=\mathbb {Z} /4\mathbb {Z} \to \mathbb {C} ^{\times }$ be a nontrivial linear representation. As ${\overline {1}}$ generates the group $G$, the group homomorphism $\rho$ is determined by its value on ${\overline {1}}.$ Because $\rho$ is a group homomorphism, it has to satisfy $\rho ({\overline {0}})=1.$ And as $\rho$ is nontrivial, we conclude $\rho ({\overline {1}})\in \{i,-1,-i\}.$ By this we achieve the result, that the image of $G$ under $\rho$ has to be a nontrivial subgroup of the group which consists of the fourth roots of unity. This means, that $\rho$ has to be one of the following three maps:

$\rho _{1}({\overline {0}})=1,\,\rho _{1}({\overline {1}})=i,\,\rho _{1}({\overline {2}})=-1,\,\rho _{1}({\overline {3}})=-i.$

$\rho _{2}({\overline {0}})=1,\,\rho _{2}({\overline {1}})=-1,\,\rho _{2}({\overline {2}})=1,\,\rho _{2}({\overline {3}})=1.$

$\rho _{3}({\overline {0}})=1,\,\rho _{3}({\overline {1}})=-i,\,\rho _{3}({\overline {2}})=-1,\,\rho _{3}({\overline {3}})=i.$

A third example:
Let $G=\mathbb {Z} /2\mathbb {Z} \times \mathbb {Z} /2\mathbb {Z}$ be a group and let $\rho :G\to {\text{GL}}_{2}(\mathbb {C} )$ be the group homomorphism defined by:

$\rho ({\overline {0}},{\overline {0}})=\left({\begin{array}{cc}1&0\\0&1\end{array}}\right),\,\,\rho ({\overline {1}},{\overline {0}})=\left({\begin{array}{cc}-1&0\\0&-1\end{array}}\right),\,\,\rho ({\overline {0}},{\overline {1}})=\left({\begin{array}{cc}0&1\\1&0\end{array}}\right),\,\,{\text{and }}\,\,\rho ({\overline {1}},{\overline {1}})=\left({\begin{array}{cc}0&-1\\-1&0\end{array}}\right).$

In this case $\rho$ is a linear representation of $G$ of degree $2.$

Permutation representation

Further information: Permutation group

Let $X$ be a finite set. Let $G$ be a group operating on $X.$ The group ${\text{Aut}}(X)$ is consequently the group of all permutations on $X$ with the composition as operation.
A group acting on a finite set is sometimes considered sufficient for the definition of the permutation representation. However, since we want to construct examples for linear representations, where groups act on vector spaces instead of on arbitrary finite sets, we have to proceed in a different way. In order to construct the permutation representation, we need a vector space $V$ with ${\text{dim}}(V)=|X|.$ A basis of $V$ can be indexed by the elements of $X.$ The permutation representation is the group homomorphism $\rho$ from $G$ to ${\text{GL}}(V)$ given by $\rho (s)e_{x}=e_{s.x}$ for all $s\in G,x\in X.$ All linear maps $\rho (s)$ are uniquely defined by this property.

Example
Let be $X=\{1,2,3\}$ and $G={\text{Per}}(3).$ Then $G$ operates on $X$ via ${\text{Aut}}(X)=G.$
The associated linear representation is $\rho :G\to {\text{GL}}(V)\cong {\text{GL}}_{3}(\mathbb {C} )$ with $\rho (\sigma )e_{x}=e_{\sigma (x)}$ for $\sigma \in G,x\in X.$

Left- and right-regular representation

Let $G$ be a group of order $g.$ Let $V$ be a vector space of dimension $g$ with a basis $(e_{t})_{t\in G}$ indexed by the elements of $G.$ The left-regular representation is a special case of the permutation representation by choosing $X=G.$ This means $\rho (s)e_{t}=e_{st}$ for all $s,t\in G.$ Thus, the family $(\rho (s)e_{1})_{s\in G}$ of images of $e_{1}$ are a basis of $V.$ The degree of the left-regular representation is equal to the order of the group.
The right-regular representation is defined similarly. As before we use a vector space $V$ with ${\text{dim}}(V)=g.$ And as before we choose again a basis of $V$ and index it with the elements of $G.$ The right-regular representation $\rho$ is defined by $\rho (s)e_{t}=e_{ts^{-1}}.$ In the same way as before $(\rho (s)e_{1})_{s\in G}$ is a basis of $V.$ Just as in the case of the left-regular representation, the degree of the right-regular representation is equal to the order of $G.$
Both representations are isomorphic via $e_{s}\mapsto e_{s^{-1}}.$ For this reason they are not always set apart, and often referred to as the regular representation.
A closer look provides the following result: A given linear representation $\rho :G\to {\text{GL}}(W)$ is isomorphic to the left-regular representation, if and only if there exists a $w\in W,$ such that $(\rho (s)w)_{s\in G}$ is a basis of $W.$

Example
Let $G$ be equal to $\mathbb {Z} /5\mathbb {Z}$ and let the representation space be $V=\mathbb {R} ^{5}.$ Let $e_{0},...,e_{4}$ be a basis of $V.$ Then the left-regular representation $L_{\rho }:G\to {\text{GL}}(V)$ is defined by $L_{\rho }(k)e_{l}=e_{k+l}$ for $k,l\in \mathbb {Z} /5\mathbb {Z} .$
The right-regular representation is defined analogously by $R_{\rho }(k)e_{l}=e_{l-k}$ for $k,l\in \mathbb {Z} /5\mathbb {Z} .$

Representations, modules and the convolution algebra

Let $G$ be a finite group, let $K$ be a commutative ring and let $K[G]$ be the group algebra of $G$ over $K.$ This algebra is free and a basis can be indexed by the elements of $G.$ Most often the basis is identified with $G.$ Every element $f\in K[G]$ can then be uniquely expressed as $\textstyle f=\sum _{s\in G}a_{s}s$ with $a_{s}\in K.$ The multiplication in $K[G]$ extends that in $G$ distributively.
Now let $V$ be a $K-$module and let $\rho :G\to {\text{GL}}(V)$ be a linear representation of $G$ in $V.$ We define $sv=\rho (s)v$ for all $s\in G$ and $v\in V.$ By linear extension $V$ is endowed with the structure of a left$-K[G]-$module. Vice versa we obtain a linear representation of $G$ starting from a $K[G]-$module $V.$ Therefore, these terms may be used interchangeably.
Suppose $K=\mathbb {C} .$ In this case the left$-\mathbb {C} [G]-$module given by $\mathbb {C} [G]$ itself corresponds to the left-regular representation. In the same way $\mathbb {C} [G]$ as a right$-\mathbb {C} [G]-$module corresponds to the right-regular representation.
In the following we will define the convolution algebra: Let $G$ be a group, the set $L^{1}(G):=\{f:G\to \mathbb {C} \}$ is a $\mathbb {C} -$vector space with the operations addition and scalar multiplication. Let $g:={\text{ord}}(G),$ then this vector space is isomorphic to $\textstyle \mathbb {C} ^{g}.$ The convolution of two elements $f,h\in L^{1}(G)$ defined by $\textstyle f*h(s):=\sum _{t\in G}f(t)h(t^{-1}s)$ makes $L^{1}(G)$ an algebra. The algebra $L^{1}(G)$ is called the convolution algebra.
The convolution algebra is free and has a basis indexed by the group elements: $(\delta _{s})_{s\in G},$ where

$\delta _{s}(t)={\begin{cases}1\,\,\,\,\,{\text{if }}\,\,\,t=s\\0\,\,\,\,\,{\text{otherwise}}\end{cases}}.$

Using the properties of the convolution we obtain: $\delta _{s}*\delta _{t}=\delta _{st}.$
We define a map between $L^{1}(G)$ and $\mathbb {C} [G],$ by defining $\delta _{s}\mapsto e_{s}$ on the basis $(\delta _{s})_{s\in G}$ and extending it linearly. Obviously the prior map is bijective. A closer inspection of the convolution of two basis elements as shown in the equation above reveals that the multiplication in $L^{1}(G)$ corresponds to that in $\mathbb {C} [G].$ Thus, the convolution algebra and the group algebra are isomorphic as algebras.
The involution $\textstyle f^{*}(s)={\overline {f(s^{-1})}}$ turns $L^{1}(G)$ into a $^{*}-$algebra. We have $\delta _{s}^{*}=\delta _{s^{-1}}.$
A representation $(\pi ,V_{\pi })$ of a group $G$ extends to a $^{*}-$algebra homomorphism

$\pi :L^{1}(G)\to {\text{End}}(V_{\pi })$

by $\pi (\delta _{s})=\pi (s).$
Since multiplicity is a characteristic property of algebra homomorphisms, $\pi$ satisfies $\pi (f*h)=\pi (f)\pi (h).$ If $\pi$ is unitary, we also obtain $\pi (f)^{*}=\pi (f^{*}).$ For the definition of a unitary representation, please refer to the chapter on properties. In that chapter we will see, that, without loss of generality, every linear representation can be assumed to be unitary.

Using the convolution algebra we can implement a Fourier transformation on a group $G.$ In the area of harmonic analysis it is shown that the following definition is consistent with the definition of the Fourier transformation on $\mathbb {R} .$
Let $\rho :G\to {\text{GL}}(V_{\rho })$ be a representation and let $f\in L^{1}(G)$ be a complex-valued function on $G$. The Fourier transform ${\hat {f}}(\rho )\in {\text{End}}(V_{\rho })$ of $f$ is defined as

${\hat {f}}(\rho )=\sum _{s\in G}f(s)\rho (s).$

It holds that ${\widehat {f*g}}(\rho )={\hat {f}}(\rho )\cdot {\hat {g}}(\rho ).$

Maps between representations

A map between two representations $(\rho ,V_{\rho }),\,(\tau ,V_{\tau })$ of the same group $G$ is a linear map $T:V_{\rho }\to V_{\tau },$ with the property that $\tau (s)\circ T=T\circ \rho (s)$ holds for all $s\in G.$
Such a map is also called $G-$linear. The kernel, the image and the cokernel of $T$ are defined by default. They are again $G-$modules. Thus, they provide representations of $G$ due to the correlation described in the previous section.

Properties

Two representations $(\rho ,V_{\rho }),(\pi ,V_{\pi })$ are called equivalent or isomorphic, if there exists a $G-$linear vector space isomorphism between the representation spaces. In other words, they are isomorphic if there exists a bijective linear map $T:V_{\rho }\to V_{\pi },$ such that $T\circ \rho (s)=\pi (s)\circ T$ for all $\,s\in G.$ In particular, equivalent representations have the same degree.

A representation $(\pi ,V_{\pi })$ is called faithful, if $\pi$ is injective. In this case $\pi$ induces an isomorphism between $G$ and the image $\pi (G).$ As the latter is a subgroup of ${\text{GL}}(V_{\pi }),$ we can regard $G$ via $\pi$ as subgroup of ${\text{Aut}}(V_{\pi }).$

Let $\rho :G\to {\text{GL}}(V)$ be a linear representation of $G.$ Let $W$ be a $G-$invariant subspace of $V,$ i.e. $\rho (s)w\in W$ for all $s\in G,w\in W.$ The restriction $\rho (s)|_{W}$ is an isomorphism of $W$ onto itself. Because $\rho (s)|_{W}\circ \rho (t)|_{W}=\rho (st)|_{W}$ holds for all $s,t\in G,$ this construction is a representation of $G$ in $W.$ It is called subrepresentation of $V.$

We can restrict the range as well as the domain:
Let $H$ be a subgroup of $G.$ Let $\rho$ be a linear representation of $G.$ We denote by ${\text{Res}}_{H}(\rho )$ the restriction of $\rho$ to the subgroup $H.$
If there is no danger of confusion, we might use only ${\text{Res}}(\rho )$ or in short ${\text{Res}}\rho .$
The notation ${\text{Res}}_{H}(V)$ or in short${\text{Res}}(V)$ is also used to denote the restriction of the representation $V$ of $G$ onto $H.$
Let $f$ be a function on $G.$ We write ${\text{Res}}_{H}(f)$ or shortly ${\text{Res}}(f)$ for the restriction to the subgroup $H.$

A representation $\rho :G\to {\text{GL}}(V)$ is called irreducible or simple, if there are no nontrivial $G-$invariant vector subspaces of $V.$ Here, as well as in the following text, we include the whole vector space as well as the zero-vector space in our definition of trivial vector subspaces. In terms of the group algebra the irreducible representations correspond to the simple $\mathbb {C} [G]-$modules.
It can be proved, that the number of irreducible representations of a group $G$ (or correspondingly the number of simple $\mathbb {C} [G]-$modules) equals the number of conjugacy classes of $G.$

A representation is called semisimple or completely reducible, if it can be written as a direct sum of irreducible representations. This is analogue to the definition of the semisimple algebra.
For the definition of the direct sum of representations please refer to the section on direct sums of representations.

A representation is called isotypic, if it is a direct sum of isomorphic, irreducible representations.

Let $(\rho ,V_{\rho })$ be a given representation of a group $G.$ Let $\tau$ be an irreducible representation of $G.$ The $\tau -$isotype $V_{\rho }(\tau )$ of $G$ is defined as the sum of all irreducible subrepresentations of $V$ isomorphic to $\tau .$
Every vector space over $\mathbb {C}$ can be provided with an inner product. A representation $\rho$ of a group $G$ in a vector space endowed with an inner product is called unitary, if $\rho (s)$ is unitary for every $s\in G.$ This means that in particular every $\rho (s)$ is diagonalizable. For more details see the article on unitary representations.
A representation is unitary with respect to a given inner product if and only if the inner product is invariant with regard to the induced operation of $G,$ that means, if $(v|u)=(\rho (s)v|\rho (s)u)$ holds for all $v,u\in V_{\rho },s\in G.$
A given inner product $(\cdot |\cdot )$ can be replaced by an invariant inner product by exchanging $(v|u)$ with $\textstyle \sum _{t\in G}(\rho (t)v|\rho (t)u).$ Thus, without loss of generality, we can assume that every further considered representation is unitary.

Example

Let $G=D_{6}=\{{\text{id}},\mu ,\mu ^{2},\nu ,\mu \nu ,\mu ^{2}\nu \}$ be the dihedral group of order $6$ generated by $\mu ,\nu$ which fulfil the properties ${\text{ord}}(\nu )=2,$ ${\text{ord}}(\mu )=3$ and $\nu \mu \nu =\mu ^{2}.$ Let $\rho :D_{6}\to {\text{GL}}_{3}(\mathbb {C} )$ be a linear representation of $D_{6}$ defined on the generators by:

$\rho (\mu )=\left({\begin{array}{ccc}{\text{cos}}({\frac {2\pi }{3}})&0&-{\text{sin}}({\frac {2\pi }{3}})\\0&1&0\\{\text{sin}}({\frac {2\pi }{3}})&0&{\text{cos}}({\frac {2\pi }{3}})\end{array}}\right),\,\,\,\,\rho (\nu )=\left({\begin{array}{ccc}-1&0&0\\0&-1&0\\0&0&1\end{array}}\right).$

This representation is faithful. The subspace $\mathbb {C} e_{2}$ is a $D_{6}-$invariant subspace. Thus, there exists a nontrivial subrepresentation $\textstyle \rho |_{\mathbb {C} e_{2}}:D_{6}\to \mathbb {C} ^{\times }$ with $\nu \mapsto -1,\mu \mapsto 1.$ Therefore, the representation is not irreducible. The mentioned subrepresentation is of degree one and irreducible. The complementary subspace of $\textstyle \mathbb {C} e_{2}$ is $D_{6}-$invariant as well. Therefore, we obtain the subrepresentation $\textstyle \rho |_{\mathbb {C} e_{1}\oplus \mathbb {C} e_{3}}$ with

$\nu \mapsto {\begin{pmatrix}-1&0\\0&1\end{pmatrix}},\,\,\,\,\mu \mapsto {\begin{pmatrix}{\text{cos}}({\frac {2\pi }{3}})&-{\text{sin}}({\frac {2\pi }{3}})\\{\text{sin}}({\frac {2\pi }{3}})&{\text{cos}}({\frac {2\pi }{3}})\end{pmatrix}}.$

This subrepresentation is also irreducible. That means, the original representation is completely reducible:

$\textstyle \rho =\rho |_{\mathbb {C} e_{2}}\oplus \rho |_{\mathbb {C} e_{1}\oplus \mathbb {C} e_{3}}.$

Both subrepresentations are isotypic and are the two only non-zero isotypes of $\rho .$
The representation $\rho$ is unitary with regard to the standard inner product on $\textstyle \mathbb {C} ^{3},$ because $\rho (\mu )$ and $\rho (\nu )$ are unitary.
Let $\textstyle T:\mathbb {C} ^{3}\to \mathbb {C} ^{3}$ be any vector space isomorphism. Then $\textstyle \eta :D_{6}\to {\text{GL}}_{3}(\mathbb {C} ),$ which is defined by the equation $\textstyle \eta (s):=T\circ \rho (s)\circ T^{-1}$ for all $s\in D_{6},$ is a representation isomorphic to $\rho .$
By restricting the domain of the representation to a subgroup, e.g. $H=\{{\text{id}},\mu ,\mu ^{2}\},$ we obtain the representation ${\text{Res}}_{H}(\rho ).$ This representation is defined by the image $\rho (\mu ),$ whose explicit form is shown above.

Constructions

The dual representation

Let $\rho :G\to {\text{GL}}(V)$ be a given representation. The dual representation or contragredient representation $\rho ^{*}:G\to {\text{GL}}(V^{*})$ is a representation of $G$ in the dual vector space of $V.$ It is defined by the property

$(\rho ^{*}(s)\alpha )(v)=\alpha (\rho (s^{-1})v)$ for all $s\in G,v\in V$ and $\alpha \in V^{*}.$

With regard to the natural pairing $\langle v^{*},v\rangle :=v^{*}(v)$ between $V^{*}$ and $V$ the definition above provides the equation:

$\langle \rho ^{*}(s)(v^{*}),\rho (s)(v)\rangle =\langle v^{*},v\rangle$ for all $s\in G,v\in V,v^{*}\in V^{*}.$

Example

Be $G=\mathbb {Z} /3\mathbb {Z} .$ Let $\rho :\mathbb {Z} /3\mathbb {Z} \to {\text{GL}}_{2}(\mathbb {C} )$ be the representation of $\mathbb {Z} /3\mathbb {Z}$ defined by:

$\rho ({\overline {0}})={\text{Id}},\,\,\rho ({\overline {1}})=\left({\begin{array}{cc}{\text{cos}}({\frac {2\pi }{3}})&-{\text{sin}}({\frac {2\pi }{3}})\\{\text{sin}}({\frac {2\pi }{3}})&{\text{cos}}({\frac {2\pi }{3}})\end{array}}\right),\,\,{\text{ and }}\,\,\rho ({\overline {2}})=\left({\begin{array}{cc}{\text{cos}}({\frac {4\pi }{3}})&-{\text{sin}}({\frac {4\pi }{3}})\\{\text{sin}}({\frac {4\pi }{3}})&{\text{cos}}({\frac {4\pi }{3}})\end{array}}\right).$

The dual representation $\rho ^{*}:\mathbb {Z} /3\mathbb {Z} \to {\text{GL}}((\mathbb {C} ^{2})^{*})$ is then given by:

$\rho ^{*}({\overline {0}})={\text{Id}},\,\,\rho ^{*}({\overline {1}})=\left({\begin{array}{cc}{\text{cos}}({\frac {4\pi }{3}})&{\text{sin}}({\frac {4\pi }{3}})\\-{\text{sin}}({\frac {4\pi }{3}})&{\text{cos}}({\frac {4\pi }{3}})\end{array}}\right),\,\,{\text{ and }}\,\,\rho ^{*}({\overline {2}})=\left({\begin{array}{cc}{\text{cos}}({\frac {2\pi }{3}})&{\text{sin}}({\frac {2\pi }{3}})\\-{\text{sin}}({\frac {2\pi }{3}})&{\text{cos}}({\frac {2\pi }{3}})\end{array}}\right).$

Direct sum of representations

Let $\textstyle (\rho _{1},V_{\rho _{1}})$ and $(\rho _{2},V_{\rho _{2}})$ be a representation of $\textstyle G_{1}$ and $\textstyle G_{2},$ respectively. The direct sum of these representations is defined as $\textstyle \rho _{1}\oplus \rho _{2}:G_{1}\times G_{2}\to {\text{GL}}(V_{\rho _{1}}\oplus V_{\rho _{2}}),$ in which $\textstyle \rho _{1}\oplus \rho _{2}(s_{1},s_{2})(v_{1},v_{2}):=\rho _{1}(s_{1})v_{1}\oplus \rho _{2}(s_{2})v_{2}$ for all $(s_{1},s_{2})\in G_{1}\times G_{2}$ and $v_{1}\in V_{\rho _{1}},v_{2}\in V_{\rho _{2}}.$
In this manner $\textstyle \rho _{1}\oplus \rho _{2}$ becomes a linear representation.
Let $\textstyle \rho _{1},\rho _{2}$ be representations of the same group $\textstyle G.$ For the sake of simplicity, the direct sum of these representations is defined as a representation of $G,$ i.e. it is given as $\textstyle \rho _{1}\oplus \rho _{2}:G\to {\text{GL}}(V_{1}\oplus V_{2}),$ by viewing $G$ as the diagonal subgroup of $\textstyle G\times G.$

Example
Let $\textstyle \rho _{1}:\mathbb {Z} /2\mathbb {Z} \to {\text{GL}}_{2}(\mathbb {C} )$ be the linear representation given by

$\rho _{1}({\overline {1}})=\left({\begin{array}{cc}0&-i\\i&0\end{array}}\right).$

And let $\textstyle \rho _{2}:\mathbb {Z} /3\mathbb {Z} \to {\text{GL}}_{3}(\mathbb {C} )$ the linear representation given by

$\rho _{2}({\overline {1}})=\left({\begin{array}{ccc}1&0&e^{\frac {2\pi i}{3}}\\0&e^{\frac {2\pi i}{3}}&0\\0&0&e^{\frac {4\pi i}{3}}\end{array}}\right).$

Then $\textstyle \rho _{1}\oplus \rho _{2}$ is a linear representation of $\textstyle \mathbb {Z} /2\mathbb {Z} \times \mathbb {Z} /3\mathbb {Z}$ in $\textstyle \mathbb {C} ^{2}\oplus \mathbb {C} ^{3}=\mathbb {C} ^{5}.$ Using the standard basis and the matrix form of the representation, the direct sum takes the following form:

$\rho _{1}\oplus \rho _{2}(k,l)=\left({\begin{array}{cc}\rho _{1}(k)&0\\0&\rho _{2}(l)\end{array}}\right),\,\,{\text{where}}\,\,k\in \mathbb {Z} /2\mathbb {Z} ,l\in \mathbb {Z} /3\mathbb {Z} .$

As it is sufficient to consider the image of the generating element, we find, that :$\rho _{1}\oplus \rho _{2}:\mathbb {Z} /2\mathbb {Z} \times \mathbb {Z} /3\mathbb {Z} \to {\text{GL}}_{5}(\mathbb {C} )$ is given by:

$\rho _{1}\oplus \rho _{2}({\overline {1}},{\overline {1}})=\left({\begin{array}{ccccc}0&-i&0&0&0\\i&0&0&0&0\\0&0&1&0&e^{\frac {2\pi i}{3}}\\0&0&0&e^{\frac {2\pi i}{3}}&0\\0&0&0&0&e^{\frac {4\pi i}{3}}\end{array}}\right).$

Tensor product of representations

Let $\rho _{1}:G_{1}\to {\text{GL}}(V_{\rho _{1}}),\,\rho _{2}:G_{2}\to {\text{GL}}(V_{\rho _{2}})$ be linear representations. We define the linear representation $\rho _{1}\otimes \rho _{2}:G_{1}\times G_{2}\to {\text{GL}}(V_{\rho _{1}}\otimes V_{\rho _{2}})$ into the tensor product of $V_{\rho _{1}}$ and $V_{\rho _{2}}$ by $\rho _{1}\otimes \rho _{2}(s_{1},s_{2})=\rho _{1}(s_{1})\otimes \rho _{2}(s_{2}),$ in which $s_{1}\in G_{1},s_{2}\in G_{2}.$ This representation is called outer tensor product of the representations $\rho _{1}$ and $\rho _{2}.$ The existence and uniqueness is a consequence of the properties of the tensor product.

Let $\rho _{1}:G\to {\text{GL}}(V_{\rho _{1}})$ and $\rho _{2}:G\to {\text{GL}}(V_{\rho _{2}})$ be two linear representations of the same group. Let $s$ be an element of $G.$ Then $\rho (s)\in {\text{GL}}(V_{\rho _{1}}\otimes V_{\rho _{2}})$ is defined by $\rho (s)(v_{1}\otimes v_{2})=\rho _{1}(s)v_{1}\otimes \rho _{2}(s)v_{2},$ for $v_{1}\in V_{\rho _{1}},v_{2}\in V_{\rho _{2}},$ and we write $\rho (s)=\rho _{1}(s)\otimes \rho _{2}(s).$ Then the map $s\mapsto \rho (s)$ defines a linear representation of $G,$ which is also called tensor product of the given representations.

These two cases have to be strictly distinguished. The first case is a representation of the group product into the tensor product of the corresponding representation spaces. The second case is a representation of the group $G$ into the tensor product of two representation spaces of this one group. But this last case can be viewed as a special case of the first one by focussing on the diagonal subgroup $G\times G.$ This definition can be iterated a finite number of times.

Let $V$ and $W$ be representations of the group $G.$ Then ${\text{Hom}}(V,W)$ is a representation by virtue of the following identity: ${\text{Hom}}(V,W)=V^{*}\otimes W$. Let $B\in {\text{Hom}}(V,W)$ and let $\rho$ be the representation on ${\text{Hom}}(V,W).$ Let $\rho _{V}$ be the representation on $V$ and $\rho _{W}$ the representation on $W.$ Then the identity above leads to the following result:

$\rho (s)(B)v=\rho _{W}(s)\circ B\circ \rho _{V}(s)v$ for all $s\in G,v\in V.$

Theorem
The irreducible representations of $G_{1}\times G_{2}$ up to isomorphism are exactly the representations $\rho _{1}\otimes \rho _{2}$ in which $\rho _{1}$ and $\rho _{2}$ are irreducible representations of $G_{1}$ and $G_{2},$respectively.

This result enables us to study the representations of $G_{1}\times G_{2}$ by studying the single representations of $G_{1}$ and $G_{2}.$

Example
We pick up again the example of the direct sum to show the difference between the direct sum and the tensor product.
Let $\textstyle \rho _{1}:\mathbb {Z} /2\mathbb {Z} \to {\text{GL}}_{2}(\mathbb {C} )$ be the linear representation given by

$\rho _{1}({\overline {1}})=\left({\begin{array}{cc}0&-i\\i&0\end{array}}\right).$

And let $\textstyle \rho _{2}:\mathbb {Z} /3\mathbb {Z} \to {\text{GL}}_{3}(\mathbb {C} )$ be the linear representation given by

$\rho _{2}({\overline {1}})=\left({\begin{array}{ccc}1&0&e^{\frac {2\pi i}{3}}\\0&e^{\frac {2\pi i}{3}}&0\\0&0&e^{\frac {4\pi i}{3}}\end{array}}\right).$

Then the outer tensor product $\rho _{1}\otimes \rho _{2}:\mathbb {Z} /2\mathbb {Z} \times \mathbb {Z} /3\mathbb {Z} \to {\text{GL}}(\mathbb {C} ^{2}\otimes \mathbb {C} ^{3})={\text{GL}}_{6}(\mathbb {C} )$ is given by $\rho _{1}(k)\otimes \rho _{2}(l),$ in which $k\in \mathbb {Z} /2\mathbb {Z} ,l\in \mathbb {Z} /3\mathbb {Z} .$
The linear map $\rho _{1}({\overline {1}})\otimes \rho _{2}({\overline {1}})$ belonging to the generating element $({\overline {1}},{\overline {1}})$ is given by:

$\rho _{1}({\overline {1}})\otimes \rho _{2}({\overline {1}})=\left({\begin{array}{cccccc}0&0&0&-i&0&-ie^{\frac {2\pi i}{3}}\\0&0&0&0&-ie^{\frac {2\pi i}{3}}&0\\0&0&0&0&0&-ie^{\frac {4\pi i}{3}}\\i&0&ie^{\frac {2\pi i}{3}}&0&0&0\\0&ie^{\frac {2\pi i}{3}}&0&0&0&0\\0&0&ie^{\frac {4\pi i}{3}}&0&0&0\end{array}}\right),$

where we used the standard basis of $\mathbb {C} ^{2}\otimes \mathbb {C} ^{3}\cong \mathbb {C} ^{6}.$
A comparison with the direct sum reveals the difference. The representations obtained in this way do not even have the same degree.

Symmetric and alternating square

Let $\rho :G\to V\otimes V$ be a linear representation of $G.$ Let $(e_{k})$ be a basis of $V.$ Define $\vartheta :V\otimes V\to V\otimes V$ by extending $\vartheta (e_{k}\otimes e_{j})=e_{j}\otimes e_{k}$ linearly. It holds $\vartheta (v\otimes u)=u\otimes v,\,\forall \,\,u,v\in V$ and $\vartheta ^{2}=1.$ Because of that $V\otimes V$ splits up into $V\otimes V={\text{Sym}}^{2}(V)\oplus {\text{Alt}}^{2}(V),$ in which

${\text{Sym}}^{2}(V)=\{z\in V\otimes V:\vartheta (z)=z\}$

and

$\textstyle {\text{Alt}}^{2}(V)=\bigwedge ^{2}(V)=\{z\in V\otimes V:\vartheta (z)=-z\}.$

These subspaces are $G-$invariant and by this define subrepresentations which are called the symmetric square and the alternating square, respectively. These subrepresentations are also defined in $V^{\otimes m},$ although in this case they are denoted wedge product $\textstyle \bigwedge ^{m}(V)$ and symmetric product ${\text{Sym}}^{m}(V).$ In case that $m>2,$ the vector space $V^{\otimes m}$ is in general not equal to the direct sum of these two products.

Decompositions

In order to understand representations more easily, a decomposition of the representation space into the direct sum of simpler subrepresentations would be desireable. This can be achieved for finite groups as we will see in the following results. More detailed explanations and proofs may be found in [1] and [2].

Theorem
This theorem is valid for vector spaces $V$ over a field of characteristic zero:
Let $\rho :G\to {\text{GL}}(V)$ be a linear representation and let $W$ be a $G-$invariant subspace of $V.$ Then the complement $\textstyle W^{0}$ of $W$ exists in $V$ and is $G-$invariant. A subrepresentation and its complement determine a representation uniquely.

The following theorem will be presented in a more general way, as it provides a very beautiful result about representations of compact – and therefore also of finite – groups:

Theorem
This theorem applies for representations over fields of characteristic zero:
Every linear representation of compact groups is a direct sum of irreducible representations.
This means in the phrasing of $K[G]-$modules: If ${\text{char}}(K)=0,$ the group algebra $K[G]$ is semisimple, i.e. it is the direct sum of simple algebras.

Note that this decomposition is not unique. However, the number of how many times a subrepresentation isomorphic to a given irreducible representation is occurring in this decomposition is independent of the choice of decomposition.

The canonical decomposition

To achieve a unique decomposition, one has to combine all the irreducible subrepresentations that are isomorphic to each other. That means, the representation space is decomposed into a direct sum of its isotypes. This decomposition is uniquely determined. It is called the canonical decomposition.
Let $(\tau _{j})_{j\in I}$ be the set of all irreducible representations of a group $G$ up to isomorphism. Let $V$ be a representation of $G$ and let $\{V(\tau _{j})|j\in I\}$ be the set of all isotypes of $V.$ The projection $p_{j}:V\to V(\tau _{j})$ corresponding to the canonical decomposition is given by

$p_{j}={\frac {n_{j}}{g}}\sum _{t\in G}{\overline {\chi _{\tau _{j}}(t)}}\rho (t),$

where $n_{j}={\text{dim}}(\tau _{j}),$ $g={\text{ord}}(G)$ and $\chi _{\tau _{j}}$ is the character belonging to $\tau _{j}.$

In the following, we show how to determine the isotype to the trivial representation:

Projection formula
Let $G$ be a group with $g={\text{ord}}(G).$ For every representation $(\rho ,V)$ of $G$ we define

$V^{G}:=\{v\in V:\rho (s)v=v\,\,\,\,\forall \,s\in G\}.$

In general, $\rho (s):V\to V$ is not $G-$linear. We define $P:={\frac {1}{g}}\sum _{s\in G}\rho (s)\in {\text{End}}(V).$ Then $P$ is a $G-$linear map, because $\textstyle \sum _{s\in G}\rho (s)=\sum _{s\in G}\rho (tst^{-1})$ for all $t\in G.$

Proposition
The map $P$ is a projection from $V$ to $V^{G}.$

This proposition enables us to determine the isotype to the trivial subrepresentation of a given representation explicitly.
The number how often the trivial representation occurs in $V$ is given by the trace of $P.$ This result is a consequence of the fact that the eigenvalues of a projection are only $0$ or $1$ and that the eigenspace corresponding to the eigenvalue $1$ is the image of the projection. Since the trace of the projection is the sum of all eigenvalues, we obtain the following result

${\text{dim}}(V(1))={\text{dim}}(V^{G})=Tr(P)={\frac {1}{g}}\sum _{s\in G}\chi _{V}(s),$

in which $V(1)$ denotes the isotype of the trivial representation and where $g={\text{ord}}(G).$
Let $V_{\pi }$ be a nontrivial irreducible representation of $G.$ Then the isotype to the trivial representation of $\pi$ is the null space. That means the following equation holds

$P={\frac {1}{g}}\sum _{s\in G}\pi (s)=0.$

Let $e_{1},...,e_{n}$ be a orthonormal basis of $V_{\pi }.$ Then we have:

$\sum _{s\in G}{\text{Tr}}(\pi (s))=\sum _{s\in G}\sum _{j=1}^{n}\langle \pi (s)e_{j},e_{j}\rangle =\sum _{j=1}^{n}\langle \sum _{s\in G}\pi (s)e_{j},e_{j}\rangle =0.$

Therefore, the following is valid for a nontrivial irreducible representation $V$:

$\sum _{s\in G}\chi _{V}(s)=0.$

Example

Let $G={\text{Per}}(3)$ be the permutation groups in three elements. Let $\rho :{\text{Per}}(3)\to {\text{GL}}_{5}(\mathbb {C} )$ be a linear representation of ${\text{Per}}(3)$ defined on the generating elements as follows:

$\rho (1,2)=\left({\begin{array}{ccccc}-1&2&0&0&0\\0&1&0&0&0\\0&0&0&1&0\\0&0&1&0&0\\0&0&0&0&1\end{array}}\right),\,\,\rho (1,3)=\left({\begin{array}{ccccc}{\frac {1}{2}}&{\frac {1}{2}}&0&0&0\\{\frac {1}{2}}&-1&0&0&0\\0&0&0&0&1\\0&0&0&1&0\\0&0&1&0&0\end{array}}\right),\,\,\rho (2,3)=\left({\begin{array}{ccccc}0&-2&0&0&0\\-{\frac {1}{2}}&0&0&0&0\\0&0&1&0&0\\0&0&0&0&1\\0&0&0&1&0\end{array}}\right).$

This representation can be decomposed on first look into the left-regular representation of ${\text{Per}}(3),$which is denoted by $\pi$ in the following, and the representation $\eta :{\text{Per}}(3)\to {\text{GL}}_{2}(\mathbb {C} )$ with

$\eta (1,2)={\begin{pmatrix}-1&2\\0&1\end{pmatrix}},\,\,\eta (1,3)={\begin{pmatrix}{\frac {1}{2}}&{\frac {1}{2}}\\{\frac {1}{2}}&-1\end{pmatrix}},\,\,\,\eta (2,3)={\begin{pmatrix}0&-2\\-{\frac {1}{2}}&0\end{pmatrix}}.$

With the help of the irreducibility criterion taken from the next chapter, we realize, that $\eta$ is irreducible and $\pi$ is not. This is, because for the inner product defined in the section ”Inner product and characters” further below, we have $(\eta |\eta )=1,(\pi |\pi )=2.$

The subspace $\mathbb {C} (e_{1}+e_{2}+e_{3})$ of $\mathbb {C} ^{3}$ is invariant with respect to the left-regular representation. Restricted to this subspace we obtain the trivial representation.
The orthogonal complement of $\mathbb {C} (e_{1}+e_{2}+e_{3})$ is $\mathbb {C} (e_{1}-e_{2})\oplus \mathbb {C} (e_{1}+e_{2}-2e_{3}).$ Restricted to this subspace, which is also $G-$invariant as we have seen above, we obtain the representation $\tau$ given by

$\tau (1,2)={\begin{pmatrix}-1&0\\0&1\end{pmatrix}},\,\,\,\tau (1,3)={\begin{pmatrix}{\frac {1}{2}}&{\frac {3}{2}}\\{\frac {1}{2}}&-{\frac {1}{2}}\end{pmatrix}},\,\,\,\,\tau (2,3)={\begin{pmatrix}{\frac {1}{2}}&-{\frac {3}{2}}\\-{\frac {1}{2}}&-{\frac {1}{2}}\end{pmatrix}}.$

Just like before we can use the irreducibility criterion of the next chapter to prove that $\tau$ is irreducible. Now, $\eta$ and $\tau$ are isomorphic, because $\eta (s)=B\circ \tau (s)\circ B^{-1}$ for all $s\in {\text{Per}}(3),$ in which $B:\mathbb {C} ^{2}\to \mathbb {C} ^{2}$ is given by the matrix

$M_{B}={\begin{pmatrix}2&2\\0&2\end{pmatrix}}.$

A decomposition of $(\rho ,\mathbb {C} ^{5})$ in irreducible subrepresentations is: $\rho =\tau \oplus \eta \oplus 1$ where $1$ denotes the trivial representation and $\mathbb {C} ^{5}=\mathbb {C} (e_{1},e_{2})\oplus \mathbb {C} (e_{3}-e_{4},e_{3}+e_{4}-2e_{5})\oplus \mathbb {C} (e_{3}+e_{4}+e_{5})$ is the corresponding decomposition of the representation space.
We obtain the canonical decomposition by combining all the isomorphic irreducible subrepresentations: $\rho _{1}:=\eta \oplus \tau$ is the $\tau -$isotype of $\rho$ and consequently the canonical decomposition is given by

$\rho =\rho _{1}\oplus 1,\,\mathbb {C} ^{5}=\mathbb {C} (e_{1},e_{2},e_{3}-e_{4},e_{3}+e_{4}-2e_{5})\oplus \mathbb {C} (e_{3}+e_{4}+e_{5}).$

The theorems above are in general not valid for infinite groups. This will be demonstrated in the following example: Let $\textstyle G=\{A\in {\text{GL}}_{2}(\mathbb {C} )|\,A\,\,{\text{ is}}{\text{ an}}{\text{ upper}}{\text{ triangular}}{\text{ matrix}}\}.$ Together with the matrix multiplication $G$ is a group of infinite cardinality. The group $G$ is acting on $\mathbb {C} ^{2}$ by matrix-vector-multiplication. We consider the representation $\rho (A)=A$ for all $A\in G.$ The subspace $\mathbb {C} e_{1}$ is a $G-$invariant subspace.
However, there exists no $G-$invariant complement to this subspace. The assumption, that such a complement exists, results in the statement, that every matrix is diagonalizable over $\mathbb {C} .$ This is known to be wrong and thus presents the contradiction.
That means, if we consider infinite groups, it is possible that a representation, although being not irreducible, can not be decomposed in a direct sum of irreducible subrepresentations.

Character theory

Definitions

Let $\textstyle \rho :G\to {\text{GL}}(V)$ be a linear representation of a finite group $\textstyle G$ into the vector space $\textstyle V.$ We define the map $\chi _{\rho }$ by$\textstyle \chi _{\rho }(s)={\text{Tr}}(\rho (s)),$ in which ${\text{Tr}}(\rho (s))$ denotes the trace of the linear map $\rho .$ The complex-valued function $\textstyle \chi _{\rho }$ obtained by this is called character of the representation $\textstyle \rho .$
Sometimes the character of a representation $\textstyle \rho$ is defined as $\textstyle \chi (s)={\text{dim}}(\rho ){\text{Tr}}(\rho (s)),$ in which $\textstyle {\text{dim}}(\rho )$ denotes the degree of the representation. In this article this definition is not used.
Based on the definition above it is obvious, that isomorphic representations have the same character.

Examples
An elementary example is a representation $\rho$ of degree one. Its character is given by $\chi =\rho .$

As another example we consider the permutation representation $V$ of $G$ corresponding to the left action of $G$ on a finite set $X.$ In this case the character is given by $\chi _{V}(s)=|\{x\in X:s.x=x\}|.$

A further example is the character $\chi _{R}$ of the regular representation $R.$
It is given by

$\chi _{R}(s)={\begin{cases}0\,\,\,\,\,\,\,\,\,\,\,\,&{\text{if }}\,\,s\neq e\\|G|\,\,\,\,\,\,&{\text{if }}\,\,s=e\end{cases}},$

where $e$ denotes the neutral element of $G.$
Note, that in this context it is correct to use the notion of regular representation and not to distinguish between left- and right-regular as they are isomorphic and thus have the same character.

As a last example we consider the group $G=\mathbb {Z} /2\mathbb {Z} \times \mathbb {Z} /2\mathbb {Z} .$ Let $\rho :G\to {\text{GL}}_{2}(\mathbb {C} )$ be the representation defined by:

$\rho ({\overline {0}},{\overline {0}})=\left({\begin{array}{cc}1&0\\0&1\end{array}}\right),\,\,\rho ({\overline {1}},{\overline {0}})=\left({\begin{array}{cc}-1&0\\0&-1\end{array}}\right),\,\,\rho ({\overline {0}},{\overline {1}})=\left({\begin{array}{cc}0&1\\1&0\end{array}}\right)\,{\text{and }}\,\,\rho ({\overline {1}},{\overline {1}})=\left({\begin{array}{cc}0&-1\\-1&0\end{array}}\right).$

The character $\chi _{\rho }$ is given by $\chi _{\rho }({\overline {0}},{\overline {0}})=2,\,\,\chi _{\rho }({\overline {1}},{\overline {0}})=-2,\,\,\chi _{\rho }({\overline {0}},{\overline {1}})=\chi _{\rho }({\overline {1}},{\overline {1}})=0.$
This example shows, that the character is in general no group homomorphism.

Properties

As shown in the section on properties of linear representations every representation can be assumed to be unitary. A character is called unitary, if it belongs to a unitary representation.
A character is called irreducible, if the corresponding representation is irreducible.
Let $\chi$ be the character of a (unitary) representation $\rho$ of degree $n.$ Then the following holds:

• $\chi (e)=n,$ where $e$ is the neutral element of $G.$
• $\chi (s^{-1})={\overline {\chi (s)}},\,\,\,\forall \,s\in G.$
• $\chi (tst^{-1})=\chi (s),\,\,\forall \,s,t\in G.$
• $\chi (s)$ is the sum of the eigenvalues of $\rho (s)$ with multiplicity.
• For $s\in G$ of order $m$ the following is valid:
  • $\chi (s)$ is the sum of $n$ $m-$th roots of unity.
  • $|\chi (g)|\leq m.$
  • $\{s\in G|\chi (s)=m\}$ is a normal subgroup in $G.$

A proof of these properties may be found in [1] and [3].

Characters of special constructions

Let $\rho _{1}:G\to {\text{GL}}(V_{\rho _{1}}),\rho _{2}:G\to {\text{GL}}(V_{\rho _{2}})$ be two linear representations of the same group $G.$ Let $\chi _{1},\chi _{2}$ be the corresponding characters. Then the following holds:

• The character $\chi _{1}^{*}$ of the dual representation $\rho _{1}^{*}$ of $\rho _{1}$ is given by $\chi _{1}^{*}={\overline {\chi _{1}}}.$
• The character $\chi$ of the direct sum $V_{\rho _{1}}\oplus V_{\rho _{2}}$ is equal to $\chi _{1}+\chi _{2}.$
• The character $\chi$ of the tensor product of the representations $V_{\rho _{1}}\otimes V_{\rho _{2}}$ is given by $\chi _{1}\cdot \chi _{2}.$
• The character $\chi$ of the representation belonging to ${\text{Hom}}(V_{\rho _{1}},V_{\rho _{2}})$ is given by ${\overline {\chi _{1}}}\cdot \chi _{2}.$

Let $\chi _{1}$ be the character of $\rho _{1}:G_{1}\to {\text{GL}}(W_{\rho _{1}})$ and $\chi _{2}$ the character of $\rho _{2}:G_{2}\to {\text{GL}}(W_{\rho _{2}}).$ Then the character $\chi$ of $\rho _{1}\otimes \rho _{2}$ is given by $\chi (s_{1},s_{2})=\chi _{1}(s_{1})\cdot \chi _{2}(s_{2}).$

Let $\rho :G\to {\text{GL}}(V)$ be a linear representation of $G$ and let $\chi$ be the corresponding character. Let $\textstyle \chi _{\sigma }^{(2)}$ be the character of the symmetric square and let $\textstyle \chi _{\alpha }^{(2)}$ be the character of the alternating square. For every $s\in G$the following holds:

${\begin{aligned}\chi _{\sigma }^{(2)}(s)&={\frac {1}{2}}(\chi (s)^{2}+\chi (s^{2}))\\\chi _{\alpha }^{(2)}(s)&={\frac {1}{2}}(\chi (s)^{2}-\chi (s^{2}))\\\chi ^{2}&=\chi _{\sigma }^{(2)}+\chi _{\alpha }^{(2)}\end{aligned}}$

Schur's lemma

Let $\rho _{1}:G\to {\text{GL}}(V_{\rho _{1}})$ and $\rho _{2}:G\to {\text{GL}}(V_{\rho _{2}})$ be two irreducible representations. Let $F:V_{\rho _{1}}\to V_{\rho _{2}}$ be a linear map such that $\rho _{2}(s)\circ F=F\circ \rho _{1}(s)$ for all $s\in G.$ Then the following is valid:

• If $\rho _{1}$ and $\rho _{2}$ are not isomorphic, we have $F=0.$
• If $V_{\rho _{1}}=V_{\rho _{2}}$ and $\rho _{1}=\rho _{2},$ $F$ is a homothety (i.e. $F=\lambda {\text{Id}}$ for a $\lambda \in \mathbb {C}$).

Proof
Suppose $F\neq 0.$ Then $F\circ \rho _{1}(s)\,(u)=\rho _{2}(s)\circ F\,(u)=0\,\,$ is valid for all $u\in {\text{ker}}(F).$ Therefore, we obtain $\rho _{1}(s)u\in {\text{ker}}(F)$ for all $s\in G$ and $u\in {\text{ker}}(F).$ And we know now, that ${\text{ker}}(F)$ is $G-$invariant. Since $V_{\rho _{1}}$ is irreducible and $F\neq 0,$ we conclude ${\text{ker}}(F)=0.$ Now let $y\in {\text{Im}}(F).$ This means, there exists a $v\in V_{\rho _{1}},$ such that $Fv=y,$ and we have $\rho _{2}(s)y=\rho _{2}(s)F\,v=F\rho _{1}(s)v.$ Thus, we deduce, that ${\text{Im}}(F)$ is a $G-$invariant subspace. Because $F\neq 0$ and $V_{\rho _{2}}$ is irreducible, we have ${\text{Im}}(F)=V_{\rho _{2}}.$ Therefore, $F$ is an isomorphism and the first statement is proven.
Suppose now that $V_{\rho _{1}}=V_{\rho _{2}},\,\,\rho _{1}=\rho _{2}.$ Since our base field is $\mathbb {C} ,$ we know that $F$ has at least one eigenvalue $\lambda .$ Let $F'=F-\lambda ,$ then ${\text{ker}}(F')\neq 0$ and we have $\rho _{2}(s)\circ F'=F'\circ \rho _{1}(s)$ for all $s\in G.$ According to the considerations above this is only possible, if $F'=0,$ i.e. $F=\lambda .$ $\Box$

Inner product and characters

In order to show some particularly interesting results about characters, it is rewarding to consider a more general type of functions on groups:

The Class functions:
A function on $G$ which fulfils the equation $\varphi (tst^{-1})=\chi (s),\,\,\forall \,s,t\in G$ is called class function. The set of all class functions $\mathbb {C} _{\text{class}}(G)=\{\varphi :G\to \mathbb {C} \,|\,\varphi (sts^{-1})=\varphi (t)\,\,\forall s,t\in G\}$ is a $\mathbb {C} -$Algebra. The dimension of $\mathbb {C} _{\text{class}}(G)$ is equal to the number of conjugacy classes of $G.$

Theorem
Let $\chi _{1},...,\chi _{k}$ be the distinct irreducible characters of $G.$ A class function on $G$ is a character of $G$ if and only if it can be written as a linear combination of the distinct irreducible characters$\chi _{j}$ with non-negative coefficients.

Proof
Let be $\varphi \in \mathbb {C} _{\text{class}}(G),$ such that $\textstyle \varphi =\sum _{j}c_{j}\chi _{j}$ where $c_{j}\in \mathbb {N} _{0}$ for all $j.$ Consequently, $\varphi$ is the character of the direct sum $\textstyle \sum _{j}c_{j}\tau _{j}$ of the representations $\tau _{j}$ corresponding to the $\chi _{j}$. Conversely, it is always possible to write any character as a sum of irreducible characters.$\Box$

Proofs of the following results of this chapter may be found in [1], [2] and [3].

An inner product can be defined on the set of all complex-valued functions $L^{1}(G)$ on a finite group:

$(f|h)_{G}={\frac {1}{|G|}}\sum _{t\in G}f(t){\overline {h(t)}}$

Also a symmetric bilinear form can be defined on $L^{1}(G):$

$\langle f,h\rangle _{G}={\frac {1}{|G|}}\sum _{t\in G}f(t)h(t^{-1})$

These two forms match on the set of characters. If there is no danger of confusion the index of both forms $(\cdot |\cdot )_{G}$ and $\langle \cdot |\cdot \rangle _{G}$will be omitted.

Let $V_{1},V_{2}$ be two $\mathbb {C} [G]-$modules. We define $\langle V_{1},V_{2}\rangle _{G}:={\text{dim}}({\text{Hom}}^{G}(V_{1},V_{2})),$ in which ${\text{Hom}}^{G}(V_{1},V_{2})$ is the vector space of all $G-$linear maps. This form is bilinear with respect to the direct sum.

In the following, these bilinear forms will allow us to obtain some important results with respect to the decomposition and irreducibility of representations.

Theorem
Let $\chi$ and $\chi '$ be the characters of two non-isomorphic irreducible representations $V$ and $V',$ respectively. Then the following is valid

• $(\chi |\chi ')=0.$
• $(\chi |\chi )=1,$ i.e. $\chi$ has „norm“ $1.$

Corollary
Let $\chi _{1}$ and$\chi _{2}$ be the characters of $V_{1}$ and $V_{2},$ respectively. Then the following holds:

$\langle \chi _{1},\chi _{2}\rangle _{G}=(\chi _{1}|\chi _{2})_{G}=\langle V_{1},V_{2}\rangle _{G}.$

This corollary is a direct consequence of the theorem above, of Schur's lemma and of the complete reducibility of representations.

Theorem
Let $V$ be a linear representation of $G$ with character $\xi .$ Let $V=W_{1}\oplus \cdots \oplus W_{k},$ where $W_{j}$ are irreducible. Let $(\tau ,W)$ be an irreducible representation of $G$ with character $\chi .$ Then it holds:
The number of subrepresentations $W_{j}$ which are isomorphic to $W$ is independent of the given decomposition and is equal to the inner product $(\xi |\chi ).$
I.e. the $\tau -$isotype $V(\tau )$ of $V$ is independent of the choice of decomposition. We also get:

$(\xi |\chi )={\frac {{\text{dim}}(V(\tau ))}{{\text{dim}}(\tau )}}=\langle V,W\rangle$

and thus

${\text{dim}}(V(\tau ))={\text{dim}}(\tau )(\xi |\chi ).$

Corollary
Two representations with the same character are isomorphic. That means, that every representation is determined by its character.

With this we obtain a very handsome result to analyse representations:

Irreducibility criterion
Let $\chi$ be the character of the representation $V,$ then we have $(\chi |\chi )\in \mathbb {N} _{0}.$ And it holds $(\chi |\chi )=1$ if and only if $V$ is irreducible.

Therefore, using the first theorem, the characters of irreducible representations of $G$ form an orthonormal set on $\mathbb {C} _{\text{class}}(G)$ with respect to this inner product.

Corollary
Let $V$ be a vector space with ${\text{dim}}(V)=n.$ A given irreducible representation $V$ of $G$ is contained $n-$times in the regular representation. That means, that if $R$ denotes the regular representation of $G$ we have: $\textstyle R\cong \oplus (W_{j})^{\oplus {\text{dim}}(W_{j})},$ in which $\{W_{j}|j\in I\}$ is the set of all irreducible representations of $G$ that are pairwise not isomorphic to each other.
In terms of the group algebra this means, that $\mathbb {C} [G]\cong \oplus _{j}{\text{End}}(W_{j})$ as algebras.

As a numerical result we get:

$|G|=\chi _{R}(e)={\text{dim}}(R)=\sum _{j}{\text{dim}}((W_{j})^{\oplus (\chi _{W_{j}}|\chi _{R})})=\sum _{j}(\chi _{W_{j}}|\chi _{R})\cdot {\text{dim}}(W_{j})=\sum _{j}{\text{dim}}(W_{j})^{2},$

in which $R$ is the regular representation and $\textstyle \chi _{W_{j}}$ and $\textstyle \chi _{R}$ are corresponding characters to $\textstyle W_{j}$ and $\textstyle R,$ respectively. It should also be mentioned, that $e$ denotes the neutral element of the group.
This formula is a necessary and sufficient condition for all irreducible representations of a group up to isomorphism. It provides us with the means to check whether we found all irreducible representations of a group up to isomorphism.
Similarly, by using the character of the regular representation evaluated at $s\neq e,$ we get the equation:

$\textstyle 0=\chi _{R}(s)=\sum _{j}{\text{dim}}(W_{j})\cdot \chi _{W_{j}}(s).$

Using the description of representations via the convolution algebra we achieve an equivalent formulation of these equations:
The Fourier inversion formula:

$f(s)={\frac {1}{|G|}}\sum _{\rho \,\,{\text{ irred.}}{\text{ rep.}}{\text{ of }}G}{\text{dim}}(V_{\rho })\cdot {\text{Tr}}(\rho (s^{-1})\cdot {\hat {f}}(\rho )).$

In addition the Plancherel formula holds:

$\sum _{s\in G}f(s^{-1})\psi (s)={\frac {1}{|G|}}\sum _{\rho \,\,{\text{ irred.}}{\text{ rep.}}{\text{ of }}G}{\text{dim}}(V_{\rho })\cdot {\text{Tr}}({\hat {f}}(\rho ){\hat {h}}(\rho )).$

In both formulas $(\rho ,V_{\rho })$ is a linear representation of a group $G,$ $s\in G$ and $f,h\in L^{1}(G).$

The corollary above has an additional consequence:

Lemma
Let $G$ be a group. Then the following is equivalent:

• $G$ is abelian.
• Every function on $G$ is a class function.
• All irreducible representations of $G$ have degree $1.$
  

Finally, we recall the definition of class functions in order to value the exceptional position of characters within them:

Orthonormal property
Let $G$ be a group. The non-isomorphic irreducible characters of $G$ form an orthonormal basis of $\mathbb {C} _{\text{class}}(G)$ with regard to the inner product defined at the beginning of this section.
I.e. for two irreducible characters $\chi$ and $\chi '$ the following is valid:

$(\chi |\chi ')={\begin{cases}1\,\,\,\,{\text{if}}\,\,\chi =\chi '\\0\,\,\,\,{\text{otherwise}}\end{cases}}.$

One might verify that the irreducible characters generate $\mathbb {C} _{\text{class}}(G)$ by showing, that there exists no class function unequal to zero which is orthogonal to all the irreducible characters.

Equivalent to the orthonormal property we have:
The number of non-isomorphic irreducible representations of a group $G$ is equal to the number of conjugacy classes of $G.$
In terms of the group algebra this means, that there are exactly as many simple $\mathbb {C} [G]-$modules (up to isomorphism) as there are conjugacy classes of $G.$

The induced representation

As was shown in the section on properties of linear representations, we can, by restricting to a subgroup, obtain a representation of a subgroup starting from a representation of a group.
Naturally we are interested in the reverse process: Is it possible to obtain the representation of a group starting from a representation of a subgroup?
We will see, that the induced representation, which will be defined in the following, provides us with the necessary concept. Admittedly, this construction is not inverse but adjoint to the restriction.

Definitions

Let $\rho :G\to {\text{GL}}(V_{\rho })$ be a linear representation of $G.$ Let $H$ be a subgroup and $\rho |_{H}$ the restriction. Let $W$ be a subrepresentation of $\rho _{H}.$ We write $\theta :H\to {\text{GL}}(W)$ to denote this representation. Let $s\in G.$ The vector space $\rho (s)(W)$ depends only on the left coset $sH$ of $s.$ Let $R$ be a representative system of $G/H,$ then $\textstyle \sum _{r\in R}\rho (r)(W)$ is a subrepresentation of $V_{\rho }.$

A representation $\rho$ of $G$ in $V_{\rho }$ is called induced by the representation $\theta$ of $H$ in $W,$ if $\textstyle V_{\rho }=\bigoplus _{r\in R}W_{r}.$ Here $R$ denotes a representative system of $G/H$ and $W_{r}=\rho (s)(W)$ for all $s\in rH$ and for all $r\in R.$

In other words:
The representation $(\rho ,V_{\rho })$ is induced by $(\theta ,W),$ if every $v\in V_{\rho }$ can be written uniquely as $\textstyle \sum _{r\in R}w_{r},$ where $w_{r}\in W_{r}$ for every $r\in R.$

We denote the representation $\rho$ of $G$ which is induced by the representation $\theta$ of $H$ as $\rho ={\text{Ind}}_{H}^{G}(\theta ),$ or in short $\rho ={\text{Ind}}(\theta ),$ if there is no danger of confusion. In mathematical notations, the representation spaces are also frequently used instead of the representation mappings, i.e. $V={\text{Ind}}_{H}^{G}(W),$ or in short $V={\text{Ind}}(W),$ if the representation V is induced by W.

Alternative description of the induced representation
By using the group algebra we obtain an alternative description of the induced representation:
Let $G$ be a group, $V$ a $\mathbb {C} [G]-$module and $W$ a $\mathbb {C} [H]-$submodule of $V$ corresponding to the subgroup $H$ of $G.$ We say, $V$ is induced by $W,$ if $V=\mathbb {C} [G]\otimes _{\mathbb {C} [H]}W,$ in which $G$ acts on the first factor: $s\cdot (e_{t}\otimes w)=e_{st}\otimes w$ for all $s,t\in G,w\in W.$

Properties

The results introduced in this section will be presented without proof. These may be found in [1] and [2].

Uniqueness and existence of the induced representation
Let $(\theta ,W_{\theta })$ be a linear representation of a subgroup $H$ of $G.$ Then there exists a linear representation $(\rho ,V_{\rho })$ of $G,$ which is induced by $(\theta ,W_{\theta }).$ Note that this representation is unique up to isomorphism.

Transitivity of induction
Let $W$ be a representation of $H.$
Let $H\leq G\leq K$ be an ascending series of groups. Then we have

${\text{Ind}}_{G}^{K}({\text{Ind}}_{H}^{G}(W))\cong {\text{Ind}}_{H}^{K}(W).$

Lemma
Let $(\rho ,V_{\rho })$ be induced by $(\theta ,W_{\theta })$ and let $\rho ':G\to {\text{GL}}(V')$ be a linear representation of $G.$ Now let $F:W_{\theta }\to V'$ be a linear map satisfying the property, that $F\circ \theta (t)=\rho '(t)\circ F$ for all $t\in G.$ Then there exists a uniquely determined linear map $F':V_{\rho }\to V',$ which extends $F$ and for which $F'\circ \rho (s)=\rho '(s)\circ F'$ is valid for all $s\in G.$
This means, that if we interpret $V'$ as a $\mathbb {C} [G]-$module, we have: ${\text{Hom}}^{H}(W_{\theta },V')\cong {\text{Hom}}^{G}(V_{\rho },V'),$ where ${\text{Hom}}^{G}(V_{\rho },V')$ is the vector space of all $\mathbb {C} [G]-$homomorphisms of $V_{\rho }$ to $V'.$ The same is valid for ${\text{Hom}}^{H}(W_{\theta },V').$

Induction on class functions
In the same way as it was done with representations, we can, using the so-called induction, obtain a class function on the group out of a class function on a subgroup.
Let $\varphi$ be a class function on $H.$ We define the function $\varphi '$ on $G$ by

$\varphi '(s)={\frac {1}{|H|}}\sum _{t\in G \atop t^{-1}st\in H}^{}\varphi (t^{-1}st).$

We say $\varphi '$ is induced by $\varphi$ and write ${\text{Ind}}_{H}^{G}(\varphi )=\varphi '$ or ${\text{Ind}}(\varphi )=\varphi '.$

Proposition
The function ${\text{Ind}}(\varphi )$ is a class function on $G.$ If $\varphi$ is the character of a representation $W$ of $H,$ then ${\text{Ind}}(\varphi )$ is the character of the induced representation ${\text{Ind}}(W)$ of $G.$

Lemma
If $\psi$ is a class function on $H$ and $\varphi$ is a class function on $G,$ we have:

${\text{Ind}}(\psi \cdot {\text{Res}}\varphi )=({\text{Ind}}\psi )\cdot \varphi .$

Theorem
Let $(\rho ,V_{\rho })$ be the representation of $G$ induced by the representation $(\theta ,W_{\theta })$ of the subgroup $H.$ Let $\chi _{\rho }$ and $\chi _{\theta }$ be the corresponding characters. Let $R$ be a representative system of $G/H.$ The induced character is given by

$\chi _{\rho }(t)=\sum _{r\in R, \atop r^{-1}tr\in H}^{}\chi _{\theta }(r^{-1}tr)={\frac {1}{|H|}}\sum _{s\in G, \atop s^{-1}ts\in H}^{}\chi _{\theta }(s^{-1}ts),$

for all $t\in G.$

Frobenius reciprocity

The message of the Frobenius reciprocity is, that the maps ${\text{Res}}$ and ${\text{Ind}}$ are adjoint to each other.
Let $W$ be an irreducible representation of $H$ and let $V$ be an irreducible representation of $G,$ then the Frobenius reciprocity tells us, that $W$ is contained in ${\text{Res}}(V)$ as often as ${\text{Ind}}(W)$ is contained in $V.$

Frobenius reciprocity

If $\psi \in \mathbb {C} _{\text{class}}(H)$ and $\varphi \in \mathbb {C} _{\text{class}}(G)$ we have

$\langle \psi ,{\text{Res}}(\varphi )\rangle _{H}=\langle {\text{Ind}}(\psi ),\varphi \rangle _{G}$

This statement is also valid for the inner product.

Proof
Every class function can be written as a linear combination of irreducible characters. As $\langle \cdot ,\cdot \rangle$ is a bilinear form, we can, without loss of generality, assume $\psi$ and $\varphi$ to be characters of irreducible representations of $H$ in $W$ and of $G$ in $V,$ respectively. We define $\psi (s)=0$ for all $s\in G\setminus H.$
Then we have

${\begin{aligned}\langle {\text{Ind}}(\psi ),\varphi \rangle _{G}&={\frac {1}{|G|}}\sum _{t\in G}{\text{Ind}}(\psi )(t)\varphi (t^{-1})\\&={\frac {1}{|G|}}\sum _{t\in G}{\frac {1}{|H|}}\sum _{s\in G \atop s^{-1}ts\in H}\psi (s^{-1}ts)\varphi (t^{-1})\\&={\frac {1}{|G|}}{\frac {1}{|H|}}\sum _{t\in G}\sum _{s\in G}\psi (s^{-1}ts)\varphi ((s^{-1}ts)^{-1})\\&={\frac {1}{|G|}}{\frac {1}{|H|}}\sum _{t\in G}\sum _{s\in G}\psi (t)\varphi (t^{-1})\\&={\frac {1}{|H|}}\sum _{t\in G}\psi (t)\varphi (t^{-1})\\&={\frac {1}{|H|}}\sum _{t\in H}\psi (t)\varphi (t^{-1})\\&={\frac {1}{|H|}}\sum _{t\in H}\psi (t){\text{Res}}(\varphi )(t^{-1})\\&=\langle \psi ,{\text{Res}}(\varphi )\rangle _{H}\end{aligned}}$

In the course of this sequence of equations we used only the definition of induction on class functions and the properties of characters. $\Box$

Alternative proof
In terms of the group algebra, i.e. by the alternative description of the induced representation, the Frobenius reciprocity is a special case of a general equation for a change of rings:

${\text{Hom}}_{\mathbb {C} [H]}(W,U)={\text{Hom}}_{\mathbb {C} [G]}(\mathbb {C} [G]\otimes _{\mathbb {C} [H]}W,U).$

This equation is by definition equivalent to

$\langle W,{\text{Res}}(U)\rangle _{H}=\langle W,U\rangle _{H}=\langle {\text{Ind}}(W),U\rangle _{G}.$

As this bilinear form tallies the bilinear form on the corresponding characters, the theorem follows without calculation. $\Box$

Mackey's irreducibility criterion

George Mackey has established a criterion to verify the irreducibility of induced representations.
For this we will first need some definitions and some specifications with respect to the notation.

Two representations $V_{1}$ and $V_{2}$ of a group $G$ are called disjoint, if they have no irreducible component in common, i.e. if $\langle V_{1},V_{2}\rangle _{G}=0.$

Let $G$ be a group and let $H$ be a subgroup. We define $H_{s}=sHs^{-1}\cap H$ for $s\in G.$
Let $(\rho ,W)$ be a representation of the subgroup $H.$ This defines by restriction a representation ${\text{Res}}_{s}(\rho )$ of $H_{s}.$ We write ${\text{Res}}_{s}(\rho )$ for ${\text{Res}}_{H_{s}}(\rho ).$ We also define another representation $\rho ^{s}$ of $H_{s}$ by $\rho ^{s}(t)=\rho (s^{-1}ts).$ These two representations are not to be confused.

Mackey's irreducibility criterion
The induced representation $V={\text{Ind}}_{H}^{G}(W)$ is irreducible if and only if the following conditions are satisfied:

• $W$ is irreducible
• For each $s\in G\setminus H$ the two representations $\rho ^{s}$ and ${\text{Res}}_{s}(\rho )$ of $H_{s}$ are disjoint.

A proof of this theorem may be found in [1].

Starting from this theorem we obtain directly the following
Corollary
Let $H$ be a normal subgroup of $G.$ Then ${\text{Ind}}_{H}^{G}(\rho )$ is irreducible if and only if $\rho$ is irreducible and not isomorphic to the conjugates $\rho ^{s}$ for $s\notin H.$

Proof
As $H$ is normal, we have $H_{s}=H$ and ${\text{Res}}_{s}(\rho )=\rho .$ Thus, the statement follows directly from the criterion of Mackey.$\Box$

Applications to special groups

In this chapter we present some applications of the so far presented theory to normal subgroups and to a special group, the semidirect product of a subgroup with an abelian normal subgroup.

Proposition
Let $A$ be a normal subgroup of the group $G$ and let $\rho :G\to {\text{GL}}(V)$ be an irreducible representation of $G.$ Then one of the following statements has to be valid:

• either there exists a true subgroup $H$ of $G,$ which contains $A,$ and an irreducible representation $\eta$ of $H,$ which induces $\rho ,$
• or the restriction of $\rho$ onto $A$ is isotypic.

If $A$ is abelian, the second point of the proposition above is equivalent to the statement, that $\rho (a)$ is a homothety for every $a\in A.$

We obtain also the following
Corollary
Let $A$ be an abelian normal subgroup of $G$ and let $\tau$ be any irreducible representation of $G.$ We denote with $(G:A)$ the index of $A$ in $G.$
Then ${\text{deg}}(\tau )|(G:A).$
If $A$ is an abelian subgroup of $G$ (not necessarily normal), generally ${\text{deg}}(\tau )|(G:A)$ is not satisfied, but nevertheless ${\text{deg}}(\tau )\leq (G:A)$ is still valid.

Now we show, how all irreducible representations of a group $G,$ which is the semidirect product of an abelian normal subgroup $A\vartriangleleft G$ and a subgroup $H\leq G,$ can be classified.

In the following, let $A$ and $H$ be subgroups of the group $G,$ where $A$ is assumed to be normal and abelian. Additionally, assume that $G$ is the semidirect product of $H$ and $A,$ i.e. $G=A\rtimes H$.
The irreducible representations of such a group $G,$ can be classified by showing that all irreducible representations of $G$ can be constructed from certain subgroups of $H$. This is the so-called method of “little groups” of Wigner and Mackey.

Since $A$ is abelian, the irreducible characters of $A$ have degree one and form the group $\mathrm {X} ={\text{Hom}}(A,\mathbb {C} ^{\times }).$ The group $G$ acts on $\mathrm {X}$ by $(s\chi )(a)=\chi (s^{-1}as)$ for $s\in G,\chi \in \mathrm {X} ,a\in A.$
Let $(\chi _{j})_{j\in \mathrm {X} /H}$ be a representative system of the orbit of $H$ in $\mathrm {X} .$ For every $j\in \mathrm {X} /H$ let $H_{j}=\{t\in H:t\chi _{j}=\chi _{j}\}.$ This is a subgroup of $H.$ Let $G_{j}=A\cdot H_{j}$ be the corresponding subgroup of $G.$ We now extend the function $\chi _{j}$ onto $G_{j}$ by $\chi _{j}(at)=\chi _{j}(a)$ for $a\in A,t\in H_{j}.$
Thus, $\chi _{j}$ is a class function on $G_{j}.$ Moreover, since $t\chi _{j}=\chi _{j}$ for all $t\in H_{j},$ it can be shown that $\chi _{j}$ is a group homomorphism from $G_{j}$ to $\mathbb {C} ^{\times }.$ Therefore, we have a representation of $G_{j}$ of degree $1,$ which is equal to its own character.
Let now $\rho$ be an irreducible representation of $H_{j}.$ Then we obtain an irreducible representation ${\tilde {\rho }}$ of $G_{j},$ by combining $\rho$ with the canonical projection $G_{j}\to H_{j}.$ Finally, we construct the tensor product of $\chi _{j}$ and ${\tilde {\rho }}.$ Thus, we obtain an irreducible representation $\chi _{j}\otimes {\tilde {\rho }}$ of $G_{j}.$
To finally obtain the classification of the irreducible representations of $G$ we use the representation $\theta _{j,\rho }$ of $G,$ which is induced by the tensor product $\chi _{j}\otimes {\tilde {\rho }}.$
Thus, we achieve the following result:

Proposition

• $\theta _{j,\rho }$ is irreducible.
• If $\theta _{j,\rho }$ and $\theta _{j',\rho '}$ are isomorphic, then $j=j'$ and additionally $\rho$ is isomorphic to $\rho '.$
• Every irreducible representation of $G$ is isomorphic to one of the $\theta _{j,\rho }.$

Amongst others, the criterion of Mackey and a conclusion based on the Frobenius reciprocity are needed for the proof of the proposition. Further details may be found in [1].

I.e. we classified all irreducible representations of $G=A\rtimes H.$

Representation ring

The representation ring of $G$ is defined as the abelian group

$R(G)=\{\sum _{j=1}^{m}a_{j}\tau _{j}|\tau _{j},j=1,...,m\,\,{\text{ all}}{\text{ irreducible}}{\text{ representations}}{\text{ of }}G\,\,{\text{ up}}{\text{ to}}{\text{ isomorphism}},a_{j}\in \mathbb {Z} \}.$

With the multiplication provided by the tensor product, $R(G)$ becomes a ring. The elements of $R(G)$ are called virtual representations.

The character defines a ring homomorphism in the set of all class functions on $G$ with complex values

${\begin{aligned}\chi :R(G)&\to \mathbb {C} _{\text{class}}(G)\\\sum a_{j}\tau _{j}&\mapsto \sum a_{j}\chi _{j},\end{aligned}}$

in which the $\chi _{j}$ are the irreducible characters corresponding to the $\tau _{j}.$

Because a representation is determined by its character, $\chi$ is injective. The images of $\chi$ are called virtual characters.
As the irreducible characters form an orthonormal basis of $\mathbb {C} _{\text{class}},$ $\chi$ induces an isomorphism

$\chi _{\mathbb {C} }:R(G)\otimes \mathbb {C} \longrightarrow \mathbb {C} _{\text{class}}(G).$

This isomorphism is defined on a basis out of elementary tensors $(\tau _{j}\otimes 1)_{j=1,...m}$ by $\chi _{\mathbb {C} }(\tau _{j}\otimes 1)=\chi _{j}$ respectively $\chi _{\mathbb {C} }(\tau _{j}\otimes z)=z\chi _{j},$ and extended bilinearly.

We write ${\mathcal {R}}^{+}(G)$ for the set of all characters of $G$ and ${\mathcal {R}}(G)$ to denote the group generated by ${\mathcal {R}}^{+}(G),$ i.e. the set of all differences of two characters. It holds ${\mathcal {R}}(G)=\mathbb {Z} \chi _{1}\oplus \cdots \oplus \mathbb {Z} \chi _{m}$ and ${\mathcal {R}}(G)={\text{Im}}(\chi )=\chi (R(G)).$ Thus, we have $R(G)\cong {\mathcal {R}}(G)$ and the virtual characters correspond to the virtual representations in an optimal manner.

Since ${\mathcal {R}}(G)={\text{Im}}(\chi )$ holds, ${\mathcal {R}}(G)$ is the set of all virtual characters. As the product of two characters provides another character, ${\mathcal {R}}(G)$ is a subring of the ring $\mathbb {C} _{\text{class}}(G)$ of all class functions on $G.$ Because the $\chi _{i}$ form a basis of $\mathbb {C} _{\text{class}}(G)$ we obtain, just as in the case of $R(G),$ an isomorphism $\mathbb {C} \otimes {\mathcal {R}}(G)\cong \mathbb {C} _{\text{class}}(G).$

Let $H$ be a subgroup of $G.$ The restriction thus defines a ring homomorphism $\textstyle {\mathcal {R}}(G)\to {\mathcal {R}}(H),\phi \mapsto \phi |_{H},$ which will be denoted by ${\text{Res}}_{H}^{G}$ or ${\text{Res}}.$ Likewise, the induction on class functions defines a homomorphism of abelian groups $\textstyle {\mathcal {R}}(H)\to {\mathcal {R}}(G),$ which will be written as ${\text{Ind}}_{H}^{G}$ or in short ${\text{Ind}}.$
According to the Frobenius reciprocity, these two homomorphisms are adjoint with respect to the bilinear forms $\langle \cdot ,\cdot \rangle _{H}$ and $\langle \cdot ,\cdot \rangle _{G}.$ Furthermore, the formula ${\text{Ind}}(\varphi \cdot {\text{Res}}(\psi ))={\text{Ind}}(\varphi )\cdot \psi$ shows that the image of

${\text{Ind}}:{\mathcal {R}}(H)\to {\mathcal {R}}(G)$

is an ideal of the ring ${\mathcal {R}}(G).$
By the restriction of representations, the map ${\text{Res}}$ can be defined analogously for $R(G),$ and by the induction we obtain the map ${\text{Ind}}$ for $R(G).$ Due to the Frobenius reciprocity, we get the result, that these maps are adjoint to each other and that the image ${\text{Im}}({\text{Ind}})={\text{Ind}}(R(H))$ is an ideal of the ring $R(G).$

If $A$ is a commutative ring, the homomorphisms ${\text{Res}}$ and ${\text{Ind}}$ may be extended to $A-$linear maps:

${\begin{aligned}A\otimes {\text{Res}}:A\otimes R(G)&\to A\otimes R(H)\\(a\otimes \sum a_{j}\tau _{j})&\mapsto (a\otimes \sum a_{j}{\text{Res}}(\tau _{j}))\end{aligned}}$

${\begin{aligned}A\otimes {\text{Ind}}:A\otimes R(H)&\to A\otimes R(G)\\(a\otimes \sum a_{j}\eta _{j})&\mapsto (a\otimes \sum a_{j}{\text{Ind}}(\eta _{j}))\end{aligned}}$

in which $\eta _{j}$ are all the irreducible representations of $H$ up to isomorphism.

With $A=\mathbb {C}$ we obtain in particular, that ${\text{Ind}}$ and ${\text{Res}}$ supply homomorphisms between $\mathbb {C} _{\text{class}}(G)$ and $\mathbb {C} _{\text{class}}(H).$

Let $G_{1}$ and $G_{2}$ be two groups with respective representations $(\rho _{1},V_{\rho _{1}})$ and $(\rho _{2},V_{\rho _{2}}).$ Then, $\rho _{1}\otimes \rho _{2}$ is the representation of the direct product $G_{1}\times G_{2}$ as was shown in a previous section. Another result of that section was, that all irreducible representations of $G_{1}\times G_{2}$ are exactly the representations $\eta _{1}\otimes \eta _{2},$ where $\eta _{1}$ and $\eta _{2}$ are irreducible representations of $G_{1}$ and $G_{2},$ respectively. This passes over to the representation ring as the identity $R(G_{1}\times G_{2})=R(G_{1})\otimes _{\mathbb {Z} }R(G_{2}),$ in which $R(G_{1})\otimes _{\mathbb {Z} }R(G_{2})$ is the tensor product of the representation rings as $\mathbb {Z} -$modules.

Artin's theorem

Theorem
Let $X$ be a family of subgroups of a finite group $G.$ Let ${\text{Ind}}:\bigoplus _{H\in X}{\mathcal {R}}(H)\to {\mathcal {R}}(G)$ be the homomorphism defined by the family of the ${\text{Ind}}_{H}^{G},\,\,H\in X.$ Then the following properties are equivalent:

• The cokernel of ${\text{Ind}}:\bigoplus _{H\in X}{\mathcal {R}}(H)\to {\mathcal {R}}(G)$ is finite.
• $G$ is the union of the conjugates of the subgroups belonging to $X,$ i.e. $G=\bigcup _{H\in X \atop s\in G}sHs^{-1}.$
  

Since ${\mathcal {R}}(G)$ is finitely generated as a group, we can rephrase the first point as follows:

• For each character $\chi$ of $G,$ there exist virtual characters $\chi _{H}\in {\mathcal {R}}(H),\,H\in X$ and an integer $d\geq 1,$ such that $d\cdot \chi =\sum _{H\in X}{\text{Ind}}_{H}^{G}(\chi _{H}).$

This theorem is valid analogically for the rings $R(H)$ and $R(G),$ because $R(G)\cong {\mathcal {R}}(G).$

Two different proofs of this theorem may be found in [1].

Corollary
Every character of $G$ is a linear combination with rational coefficients of characters induced by characters of cyclic subgroups of $G.$

This is a direct consequence of Artin's theorem, because $G$ is the union of all the conjugates of its cyclic subgroups.

Brauer's theorem

First we need some definitions:

A group is called $p-$elementary, if it is the direct product of a cyclic group of prime order $p$ and a $p-$group. A subgroup of $G$ is called elementary, if it is $p-$elementary for at least one prime number $p.$
A representation of $G$ is called monomial, if it is induced by a degree$-1-$representation of a subgroup of $G.$

Brauer's Theorem

Every character of $G$ is a linear combination with integer coefficients of characters induced by characters of elementary subgroups.

A proof and a detailed explanation to Brauer's theory may be found in [1] and [6].

Since $p-$elementary groups are nilpotent and thus supersolvable, the following theorem taken from [1] can be applied:

Theorem
Let $G$ be a supersolvable group. Then every irreducible representation of $G$ is induced by a representation of degree $1$ of a subgroup of $G.$ I.e. every irreducible representation of $G$ is monomial.

Thus, we achieve the following result of Brauer's theorem:

Theorem

Every character of $G$ is a linear combination with integer coefficients of monomial characters.

Real representations

For proofs and more information about representations over general subfields of $\mathbb {C}$ please refer to [2].

If a group $G$ acts on a real vector space $V_{0},$ the corresponding representation on the vector space $V=V_{0}\otimes _{\mathbb {R} }\mathbb {C}$ is called real.
The vector space $V=V_{0}\otimes _{\mathbb {R} }\mathbb {C}$ is a complex vector space also called complexification of $V_{0}.$ The corresponding representation mentioned above is given by $s.(v_{0}\otimes z)=(s.v_{0})\otimes z$ for all $s\in G,v_{0}\in V_{0},z\in \mathbb {C} .$
Let $\rho$ be a real representation. The linear map $\rho (s)$ is real-valued for all $s\in G.$ Thus, we can conclude, that the character of a real representation is always real-valued.
But not every representation with a real-valued character is real. To make this clear, let $G\subset {\text{SU}}(2)$ be a finite, non-abelian subgroup of the group

$SU(2)=\{{\begin{pmatrix}a&b\\-{\overline {b}}&{\overline {a}}\end{pmatrix}}:\,\,|a|^{2}+|b|^{2}=1\}.$

Then $G$ acts on $V=\mathbb {C} ^{2}.$ Since the trace of a matrix in ${\text{SU}}(2)$ is real, the character of the representation is real-valued.
Suppose $\rho$ would be a real representation, then $G$ would consist only of real-valued matrices. Thus, $G$ would be a subgroup of the circle group ${\text{SU}}(2)\cap {\text{GL}}_{2}(\mathbb {R} )={\text{SO}}(2)=S^{1}.$ The circle group is abelian and so are all its subgroups, especially $G.$ But $G$ was chosen to be a non-abelian group.
Now we only need to prove the existence of such a non-abelian, finite subgroup of ${\text{SU}}(2).$ To find such a group, observe that ${\text{SU}}(2)$ can be identified with the units of the quaternions. Now let $G=\{\pm 1,\pm i,\pm j,\pm ij\}.$ We will now give an example of a two-dimensional representation of $G,$ which is not real-valued, but has a real-valued character:
Let $\rho :G\to {\text{GL}}_{2}(\mathbb {C} )$be a group homomorphism determined by:

$\rho (1)={\text{E}}_{2},\rho (-1)=-{\text{E}}_{2}$

$\rho (i)={\begin{pmatrix}i&0\\0&-i\end{pmatrix}},\rho (j)={\begin{pmatrix}0&i\\i&0\end{pmatrix}}.$

Then the image of $\rho$ is not real-valued, but nevertheless it is a subset of ${\text{SU}}(2).$ Thus, the character of the representation is real.

Lemma
An irreducible representation $V$ of $G$ is real if and only if there exists a nondegenerate symmetric bilinear form $B$ on $V$ preserved by $G.$

An irreducible representation of $G$ on a vector space with base field $\mathbb {R}$ can become reducible when extending the field to $\mathbb {C} .$ An example is the irreducible representation of the cyclic group $\mathbb {Z} /m\mathbb {Z}$ in $\mathbb {R} ^{2},$ given by

$k\mapsto {\begin{pmatrix}{\text{cos}}({\frac {2\pi ik}{m}})&{\text{sin}}({\frac {2\pi ik}{m}})\\-{\text{sin}}({\frac {2\pi ik}{m}})&{\text{cos}}({\frac {2\pi ik}{m}})\end{pmatrix}},$

which is reducible when considered over $\mathbb {C} .$
I.e. by classifying all the irreducible representations that are real over $\mathbb {C} ,$ we still haven't classified all the irreducible real representations.
But we achieve the following:
Let $V_{0}$ be a real vector space. Let $G$ act irreducibly on $V_{0}$ and let $V=V_{0}\otimes \mathbb {C}$ be the corresponding real representation of $G.$ If $V$ is not irreducible, there are exactly two irreducible factors which are complex conjugate representations of $G.$

Definition
A quaternionic representation is a (complex) representation $V,$ which possesses a $G-$invariant anti-linear homomorphism $J:V\to V$ satisfying $J^{2}=-{\text{Id}}.$
Thus, a skew-symmetric, nondegenerate $G-$invariant bilinear form defines a quaternionic structure on $V.$

Theorem
An irreducible representation $V$ is one and only one of the following:

• complex: $\chi _{V}$ is not real-valued and there exists no $G-$invariant nondegenerate bilinear form on $V.$
• real: $V=V_{0}\otimes \mathbb {C} ,$ a real representation; $V$ has a $G-$invariant nondegenerate symmetric bilinear form.
• quaternionic: $\chi _{V}$ is real, but $V$ is not real; $V$ has a $G-$invariant skew-symmetric nondegenerate bilinear form.

Outlook—Representations of compact groups

The theory of representations of compact groups may be, to some degree, extended to locally compact groups. The representation theory unfolds in this context great importance for harmonic analysis and the study of automorphic forms. For proofs, further information and for a more detailed insight which is beyond the scope of this chapter please consult [4] and [5].

Definition and properties

A topological group is a group together with a topology with respect to which the group composition and the inversion are continuous. Such a group is called compact, if any cover of $G,$ which is open in the topology, has a finite subcover. Closed subgroups of a compact group are compact again.

Let $G$ be a compact group and let $V$ be a finite-dimensional $\mathbb {C} -$vector space. A linear representation of $G$ to $V$ is a continuous group homomorphism $\rho :G\to {\text{GL}}(V),$ i.e. $\rho (s)v$ is a continuous function in the two variables $s\in G$ and $v\in V.$
A linear representation of $G$ into a Banach space $V$ is defined to be a continuous group homomorphism of $G$ into the set of all bijective bounded linear operators on $V$ with a continuous inverse. Since $\pi (g)^{-1}=\pi (g^{-1}),$ we can do without the last requirement. In the following, we will consider in particular representations of compact groups in Hilbert spaces.

Just as with finite groups, we can define the group algebra and the convolution algebra. However, the group algebra provides no helpful information in the case of infinite groups, because the continuity condition gets lost during the construction. Instead the convolution algebra $L^{1}(G)$ takes its place.

Most properties of representations of finite groups can be transferred with appropriate changes to compact groups. For this we need a counterpart to the summation over a finite group:

Existence and uniqueness of the Haar measure on $G$
On a compact group $G$ there exists exactly one measure $dt,$ such that:

• $\int _{G}^{}f(t)dt=\int _{G}f(st)dt$ for all $s\in G,$ i.e. the measure is left-translation-invariant.
• $\int _{G}dt=1,$ thus the whole group has measure $1.$

Such a left-translation-invariant, normed measure is called Haar measure of the group $G.$
Since $G$ is compact, it is possible to show that this measure is also right-translation-invariant, i.e. it also applies

• $\int _{G}^{}f(t)dt=\int _{G}f(ts)dt$ for all $s\in G.$

By the scaling above the Haar measure on a finite group is given by $dt(s)={\frac {1}{|G|}}$ for all $s\in G.$

All the definitions to representations of finite groups, that are mentioned in the section ”Properties”, also apply to representations of compact groups. But there are some modifications needed:
To define a subrepresentation we now need a closed subspace. This was not necessary for finite-dimensional representation spaces, because in this case every subspace is already closed. Furthermore, two representations $\rho ,\pi$ of a compact group $G$ are called equivalent, if there exists a bijective, continuous, linear operator $T$ between the representation spaces whose inverse is also continuous and which satisfies $T\circ \rho (s)=\pi (s)\circ T$ for all $s\in G.$
If $T$ is unitary, the two representations are called unitary equivalent.
To obtain a $G-$invariant inner product from a not $G-$invariant, we now have to use the integral over $G$ instead of the sum. If $(\cdot |\cdot )$ is an inner product on a Hilbert space $V,$ which is not invariant with respect to the representation $\rho$ of $G,$ then

$(v|u)_{\rho }=\int _{G}(\rho (t)v|\rho (t)u)dt$

is a $G-$invariant inner product on $V$ due to the properties of the Haar measure$dt.$
Thus, we can assume every representation on a Hilbert space to be unitary.

Let $G$ be a compact group and let $s\in G.$ Let $L^{2}(G)$ be the Hilbert space of the square integrable functions on $G.$ We define the operator $L_{s}$ on this space by $L_{s}\Phi (t)=\Phi (s^{-1}t),$ where $\Phi \in L^{2}(G),t\in G.$
The map $s\mapsto L_{s}$ is a unitary representation of $G.$ It is called left-regular representation. The right-regular representation is defined similarly. As the Haar measure of $G$ is also right-translation-invariant, the operator $R_{s}$ on $L^{2}(G)$ is given by $R_{s}\Phi (t)=\Phi (ts).$ The right-regular representation is then the unitary representation given by $s\mapsto R_{s}.$ The two representations $s\mapsto L_{s}$ and $s\mapsto R_{s}$ are dual to each other.
If $G$ is infinite, these representations have no finite degree. The left- and right-regular representation as defined at the beginning are isomorphic to the left- and right-regular representation as defined above, if the group $G$ is finite. This is due to the fact, that in this case $L^{2}(G)\cong L^{1}(G)\cong \mathbb {C} [G].$

Constructions and decompositions

The different ways of constructing new representations from given ones can be used for compact groups as well, except for the dual representation with which we will deal later. The direct sum and the tensor product with a finite number of summands/factors are defined in exactly the same way as for finite groups. This is also the case for the symmetric and alternating square. Additionally, we need a Haar measure on the direct product of groups in order to obtain also for compact groups the result, that the irreducible representations of the product of two groups are, up to isomorphism, exactly the tensor product of the irreducible representations of the single groups. The direct product of two compact groups $G_{1}\times G_{2}$ is again a compact group, if provided with the product topology. The Haar measure on this group is given by the product of the Haar measures of the single groups.
For the dual representation on compact groups we require the topological dual $V'$ of the vector space $V.$ This is the vector space of all continuous linear functionals from the vector space $V$ into the base field. Let $\pi$ be a representation of a compact group $G$ in $V.$
The dual representation $\pi ':G\to {\text{GL}}(V')$ is defined by the property $\langle \pi '(s)v',\pi (s)v\rangle =\langle v',v\rangle :=v'(v)$ for all $v\in V,v'\in V',s\in G.$ Thus, we can conclude, that the dual representation is given by $\pi '(s)v'=v'\circ \pi (s^{-1})$ for all $v'\in V',s\in G.$ The map $\pi '$ is again a continuous group homomorphism and thus a representation.
On Hilbert spaces: $\pi$ is irreducible if and only if $\pi '$ is irreducible.

By transferring the results of the section decompositions to compact groups, we obtain the following theorems:

Theorem
Every irreducible representation $(\tau ,V_{\tau })$ of a compact group $(\tau ,V_{\tau })$ into a Hilbert space is finite-dimensional and there exists an inner product on $V_{\tau }$ such that $\tau$ is unitary. Since the Haar measure is normalized, this inner product is unique.
Every representation of a compact group is isomorphic to a direct Hilbert sum of irreducible representations.

Let $(\rho ,V_{\rho })$ be a unitary representation of the compact group $G.$ Just as for finite groups we define for an irreducible representation $(\tau ,V_{\tau })$ the isotype or isotypic component in $\rho$ to be the subspace

$V_{\rho }(\tau )=\sum _{U\subset V_{\rho } \atop U\cong V_{\tau }}U.$

This is the sum of all invariant closed subspaces $U,$ which are $G-$isomorphic to $V_{\tau }.$
Note, that the isotypes of not equivalent irreducible representations are pairwise orthogonal.

Theorem

• $V_{\rho }(\tau )$ is a closed invariant subspace of $V_{\rho }.$
• $V_{\rho }(\tau )$ is $G-$isomorphic to the direct sum of copies of $V_{\tau }.$
• $V_{\rho }$ is the direct Hilbert sum of the isotypes $V_{\rho }(\tau ),$ in which $\tau$ passes through all the isomorphism classes of the irreducible representations. This decomposition of $V_{\rho }$ is called the canonical decomposition.

The corresponding projection to the canonical decomposition $p_{\tau }:V\to V(\tau ),$ in which $V(\tau )$ is an isotype of $V,$ is for compact groups given by

$p_{\tau }(v)=n_{\tau }\int _{G}{\overline {\chi _{\tau }(t)}}\rho (t)(v)dt,$

where $n_{\tau }={\text{dim}}(V(\tau ))$ and $\chi _{\tau }$ is the character corresponding to the irreducible representation $\tau .$

Projection formula
For every representation $(\rho ,V)$of a compact group $G$ we define $V^{G}=\{v\in V:\rho (s)v=v\,\,\,\forall s\in G\}.$
In general $\rho (s):V\to V$ is not $G-$linear. Let be $\textstyle Pv:=\int _{G}\rho (s)vds.$ The map $P$ is defined as endomorphism on $V$ by having the property

$(\int _{G}\rho (s)vds|w)=\int _{G}(\rho (s)v|w)ds,$

which is valid for the inner product of the Hilbert space $V.$

Then $P$ is $G-$linear, because of

${\begin{aligned}(\int _{G}\rho (s)(\rho (t)v)ds|w)&=\int _{G}(\rho (tst^{-1})(\rho (t)v)|w)ds\\&=\int _{G}(\rho (ts)v|w)ds\\&=\int (\rho (t)\rho (s)v|w)ds\\&=(\rho (t)\int _{G}\rho (s)vds|w),\end{aligned}}$

where we used the invariance of the Haar measure.

Proposition
The map $P$ is a projection from $V$ to $V^{G}.$

If the representation is finite-dimensional, it is possible to determine the direct sum of the trivial subrepresentation just as in the case of finite groups.

Characters, Schur's lemma and the inner product

Generally, representations of compact groups are investigated on Hilbert- and Banach spaces. In most cases they are not finite-dimensional. Therefore, it is not useful to refer to characters when speaking about representations of compact groups. Nevertheless in most cases it is possible to restrict the study to the case of finite dimensions:
Since irreducible representations of compact groups are finite-dimensional and unitary (see results from the first subsection), we can define irreducible characters in the same way as it was done for finite groups.
As long as the constructed representations stay finite-dimensional, the characters of the newly constructed representations may be obtained in the same way as for finite groups.

Schur's lemma is also valid for compact groups:
Let $(\pi ,V)$ be an irreducible unitary representation of a compact group $G.$ Then every bounded operator $T:V\to V$ satisfying the property $T\circ \pi (s)=\pi (s)\circ T$for all $s\in G,$ is a scalar multiple of the identity, i.e. there exists $\lambda \in \mathbb {C}$ such that $T=\lambda {\text{Id}}.$

Defintions
The formula

$(\Phi |\Psi )=\int _{G}\Phi (t){\overline {\Psi (t)}}dt.$

defines an inner product on the set of all square integrable functions $L^{2}(G)$ of a compact group $G.$
Likewise

$\langle \Phi ,\Psi \rangle =\int _{G}\Phi (t)\Psi (t^{-1})dt.$

defines a bilinear form on $L^{2}(G)$ of a compact group $G.$
The bilinear form on the representation spaces is defined exactly as it was for finite groups.

Analogous to finite groups the following results are therefore valid:

Theorem
Let $\chi$ and $\chi '$ be the characters of two non-isomorphic irreducible representations $V$ and $V',$ respectively. Then the following is valid

• $(\chi |\chi ')=0.$
• $(\chi |\chi )=1,$ i.e. $\chi$ has „norm“ $1.$

Theorem
Let $V$ be a representation of $G.$ Let $V=W_{1}\oplus \cdots \oplus W_{k},$ in which the $W_{i}$ are irreducible. As the direct sum is finite, the sum of the irreducible characters corresponding to the $W_{i}$ defines a character $\xi$ of $V.$ Let now $(\tau ,W)$ be an irreducible representation of $G$ with character $\chi .$ Then we have:
The number of subrepresentations $W_{i}$ equivalent to $W$ are independent of the given decomposition and is equal to the inner product $(\xi |\chi ).$
I.e. the $\tau -$isotype $V(\tau )$ of $V$ is independent of the choice of the decomposition and it holds:

${\text{dim}}(W)(\xi |\chi )={\text{dim}}(V(\tau ))={\text{dim}}(W)\langle V,W\rangle .$

Theorem
Two irreducible representations with the same character are isomorphic.

Irreducibility criterion
Let $\chi$ be the character of the representation $V,$ then $(\chi |\chi )\in \mathbb {N} _{0}.$ Additionally $(\chi |\chi )=1$ if and only if $V$ is irreducible.

Therefore, using the first theorem, the characters of irreducible representations of $G$ form an orthonormal set on $L^{2}(G)$ with respect to this inner product.

Corollary
Every irreducible representation $V$ of $G$ is contained ${\text{dim}}(V)-$times in the left-regular representation.

Lemma
Let $G$ be a compact group. Then the following statements are equivalent:

• $G$ is abelian.
• All the irreducible representations of $G$ have degree $1.$

Orthonormal property
Let $G$ be a group. The non-isomorphic irreducible representations of $G$ form an orthonormal basis in $L^{2}(G)$ with respect to this inner product.

As we already know, that the non-isomorphic irreducible representations are orthonormal, we only need to verify, that they generate $L^{2}(G).$ This may be done, by proving, that there exists no non-zero square integrable function on $G$ orthogonal to all the irreducible characters.

Just as in the case of finite groups we note: The number of the irreducible representations up to isomorphism of a group $G$ equals the number of conjugacy classes of $G.$ However, because a compact group has in general infinitely many conjugacy classes, this does not provide any useful information.

The induced representation

If $H$ is a closed subgroup of finite index in the compact group $G,$ the definition of the induced representation for finite groups may be adopted.
However, the induced representation can be defined more generally, so that the definition is valid independent of the index of the subgroup $H.$
For this purpose let $(\eta ,V_{\eta })$ be a unitary representation of the closed subgroup $H.$ The continuous induced representation ${\text{Ind}}_{H}^{G}(\eta )=(I,V_{I})$ is defined as follows:
Let $V_{I}$ denote the Hilbert space of all measurable, square integrable functions $\Phi :G\to V_{\eta }$ with the property $\Phi (ls)=\eta (l)\Phi (s)$ for all $l\in H,s\in G.$ The norm is given by $||\Phi ||_{G}={\text{sup}}_{s\in G}||\Phi (s)||$ and the representation $I$ is given as the right-translation: $I(s)\Phi (k)=\Phi (ks).$
The induced representation is then again a unitary representation.
Since $G$ is compact, the induced representation can be decomposed into the direct sum of irreducible representations of $G.$ Note, that all irreducible representations belonging to the same isotype appear with a multiplicity equal to ${\text{dim}}({\text{Hom}}_{G}(V_{\eta },V_{I}))=\langle V_{e}ta,V_{I}\rangle _{G}.$
Let $(\rho ,V_{\rho })$ be a representation of $G,$ then there exists a canonical isomorphism

$T:{\text{Hom}}_{G}(V_{\rho },I_{H}^{G}(\eta ))\to {\text{Hom}}_{H}(V_{\rho }|_{H},V_{\eta }).$

The Frobenius reciprocity transfers, together with the modified definitions of the inner product and of the bilinear form, to compact groups. The theorem now holds for square integrable functions on $G$ instead of class functions and the subgroup $H$ must be closed.

Theorem of Peter-Weyl

Further information: Peter-Weyl theorem

Another important result in the representation theory of compact groups is the Theorem of Peter-Weyl. It is usually presented and proved in the harmonic analysis, as it represents one of its central and fundamental statements.

Theorem of Peter-Weyl
Let $G$ be a compact group. For every irreducible representation $(\tau ,V_{\tau })$ of $G$ let $e_{1},...,e_{{\text{dim}}(\tau )}$ be an orthonormal basis of $V_{\tau }.$

We define the matrix coefficients $\tau _{k,l}(s)=\langle \tau (s)e_{k},e_{l}\rangle$ for $1\leq k,l\leq {\text{dim}}(\tau ),s\in G.$
Then

$({\sqrt {{\text{dim}}(\tau )}}\tau _{k,l})_{k,l}$

is an orthonormal basis of $L^{2}(G).$

Second version of the Theorem of Peter-Weyl
There exists a natural $G\times G-$isomorphism

$L^{2}(G)\cong _{G\times G}{\widehat {\oplus }}_{\tau \in {\hat {G}}}{\text{End}}(V_{\tau })\cong _{G\times G}{\widehat {\oplus }}_{\tau \in {\hat {G}}}\tau \otimes \tau ^{*}$

in which ${\hat {G}}$ is the set of all irreducible representations of $G$ up to isomorphism and $V_{\tau }$ is the representation space corresponding to $\tau .$

This isomorphism maps a given $\Phi \in L^{2}(G)$ onto $\sum _{\tau \in {\hat {G}}}\tau (\Phi ),$ where

$\tau (\Phi )=\int _{G}\Phi (t)\tau (t)dt\in {\text{End}}(V_{\tau }).$

Thus, we have a generalisation of the Fourier series for functions on compact groups.
Actually, this theorem is just a reformulation of the first version.

A proof of this theorem and more information regarding the representation theory of compact groups may be found in [5].

Literature

• [1] Serre, Jean-Pierre: Linear Representations of Finite Groups. Springer Verlag, New York 1977, ISBN 0-387-90190-6.
• [2] Fulton, William; Harris, Joe: Representation Theory A First Course. Springer-Verlag, New York 1991, ISBN 0-387-97527-6.
• [3] Alperin, J.L.; Bell, Rowen B.: Groups and Representations Springer-Verlag, New York 1995, ISBN 0-387-94525-3.
• [4] Deitmar, Anton: Automorphe Formen Springer-Verlag 2010, ISBN 978-3-642-12389-4, p.89-93,185-189
• [5] Echterhoff, Siegfried; Deitmar, Anton: Principles of harmonic analysis Springer-Verlag 2009, ISBN 978-0-387-85468-7, p.127-150
• [6] Lang, Serge: Algebra Springer-Verlag, New York 2002, ISBN 0-387-95385-X, p. 663-729