1806 North Carolina gubernatorial election
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The 1806 North Carolina gubernatorial election was held on 27 November 1806 in order to elect the governor of North Carolina. Incumbent Democratic-Republican governor Nathaniel Alexander was re-elected by the North Carolina General Assembly as he ran unopposed.[1]
General election
[edit]On election day, 27 November 1806, incumbent Democratic-Republican governor Nathaniel Alexander was re-elected by the North Carolina General Assembly, thereby retaining Democratic-Republican control over the office of governor. Alexander was sworn in for his second term on 1 December 1806.[2]
Results
[edit]| Party | Candidate | Votes | % | |
|---|---|---|---|---|
| Democratic-Republican | Nathaniel Alexander (incumbent) | 100 | 100.00 | |
| Total votes | 100 | 100.00 | ||
| Democratic-Republican hold | ||||
References
[edit]- ^ "Nathaniel Alexander". National Governors Association. 5 January 2013. Retrieved 16 May 2024.
- ^ "NC Governor". ourcampaigns.com. 6 January 2008. Retrieved 16 May 2024.
Categories:
- 1806 North Carolina elections
- North Carolina gubernatorial elections
- November 1806 events
- 1806 United States gubernatorial elections
- 1806 in North Carolina
- 1800s in North Carolina
- Indirect elections
- Single-candidate elections
- 1800s North Carolina elections
- 1806 elections
- 1806 elections in North America
- 1806 elections in the United States
- Government of North Carolina
- United States gubernatorial elections in the 1800s