Talk:Recoil

I don't think this article is accurate. In most small arms, most of the recoil does not come from conservation of momentum with the bullet itself, as the article asserts. Instead, it comes from the rapid escape of gasses after the bullet exits the muzzle. The recoil due to the opposing force of the bullet itself is usually quite small. However, I am not an expert on recoil (as I am attempting to learn more about it myself), so I do not think I can correct the article. AaronWL 00:52, 19 February 2006 (UTC)

You are partially correct. The recoil energy of a small arm is determined by the total chemical energy held within the powder charge. The muzzle energy of a small arm as calculated by the projectile is about one-third the total chemical energy of the powder charge. There are two different equations for figuring muzzle energy and recoil energy. Greg Glover 15:00, 3 October 2006 (UTC)

Depends on the caliber. A .45 ACP uses a 230 grain bullet, and about 7 grains of powder; in this case the bullet generates nearly all the recoil. In a .22-250 Remington varmint load, the bullet is about 40 grains and 35-40 grains of powder, so the recoil is as much powder as bullet. scot 18:13, 2 October 2006 (UTC)

Stuff to be done

• Tie in muzzle brakes, along with examples above of powder/bullet masses.
• Add issues of recoil and controllability with rapid fire
• Bore height and muzzle rise
• Shotgun recoil absorbing stocks
• Recoil absorbing materials (sorbothane, neoprene)

This artical is completly inaccurate (wrong). I will rewrite the artical this week.

The major problem with this artical is the the author incorectly believes recoil is momentum. Recoil is not momentum. Momentum is a measurement of velocity. Recoil is a measurement of energy: From Newton's second law; F=ma. edited Greg Glover 16:09, 3 October 2006 (UTC)

On the contrary, recoil IS momentum, pure and simple. You push a bullet (and powder mass) one way, the gun goes the other way, that's conservation of momentum, period. How do you think that gun gets its velocity?

Measurements of energy are stated in units of foot-pound force (ft-lb_f). Therefor all measurements in "free recoil" are staed in foot-pound force. As in: a Winchester Model 70 that weighs 9 pounds including scope and chambered for a Spingfield .30-06' loaded with a 180 grain bullet will impart to your shoulder 20.6ft-lb_f of "free recoil" to your shoulder.

But again, energy is not the whole equation, otherwise a 40 grain bullet at 4000 fps would interchangeable with a 500 grain bullet at 1100 fps. It's not, because momentum and energy interact in entirely different ways. Recoil is generated by conservation of momentum; how you choose to express it, whether in momentum, energy, velocity, or "Marcus Inches", is up to you. (The Marcus Inch, BTW, was a measure of how far back Marcus' shoulder was kicked when firing a given handgun. A .45-70 T/C generated a good 8 Marcus Inches of recoil.)

I wish I could get the credit for creating a set of Units of Measure (Marcus Inches of recoil) but I have to give that credit to Sir Isaac Newton. I think you are mixing Apples and Oranges. Bullet velocity to firearm velocity is not comparable and is not Newton third law.

56 grains of H4350 has about 10,000ft-lbf of chemical energy. Only about one third of that chemical energy is imparted to the base of a bullet. However all 10,000ft-lbf are imparted to the firearm. Also that said bullet weighs 180 grains, said rifle weighs 70,000 grains. Can you visualize the difference?

Greg Glover 3:16 (PDT)

"Felt recoil" has no known equation that I am awear of.

This is true, yet you claim that recoil energy is the only issue of consequence; I claim that energy, momentum, and duration all count in how the shooter perceives recoil. Read last month's Dillon Precision catalog, on the 255 grain .45 ACP load; it has a 170 power factor, yet has a far lower perceived recoil than the 200 grain PF 170 the author was previously using. With identical power factors (which is a measure of momentum), the gun is going to recoil at exactly the same velocity, so why is there a difference in felt recoil?

When I get home tonight I will run the numbers and tell what the differences are tomarrow. Also the "Power Factor" you sight was an equation created by a group of competitive handgun shoots (the name escape me) circa 1978 for classifying different calibers of handguns to make the competitive fair and equitable (eg a .380 ACP vs .357 Bains & Davis ).Greg Glover: 4:05 2 OCT 06 (PDT)

Greg Glover: Formost expert on transitional kinetic energy 2:16 2 OCT 06 (PDT)

Yeah, well forgive me if I ask for references to back that one up. I've written both internal and external ballistics simulation sofware (for personal use, not sale), so I'm pretty well aquainted with the physics involved. scot 21:38, 2 October 2006 (UTC)

The law determing recoil is conservation of momentum, which is mass times velocity, not kinetic energy, which is the integral with respect to velocity of momentum (hence mass times 0.5 times velocity squared). Conservation of momentum determines the free recoil velocity of the firearm; from this the recoil energy can be calculated. Perception of recoil has much to do with the free recoil velocity, but the mass of the recoiling object still counts, because that determines how much the recoiling firearm can accelerate the shooter's body as it transfers the momentum on. A 1 lb. pistol recoiling at 10 f/s is going to disturb the shooter much less than a 10 lb. rifle recoiling at 10 f/s. The recoil energy, which is more tied to velocity than mass, determines how whether the recoil is "soft" or "sharp". A .38 Spl firing a 158 grain bullet at 700 fps beats a .221 Remington Fireball firing 40 grains at 2500 fps, but the feel of the recoil is far, far different since the .221 is accelerating the gun in a small fraction of the time the .38 is. IF the gun was placed a few inches from the shooter upon firing, so that it reached full velocity by the time it hit, it wouldn't matter, but it is firmly attached to the shooter at firing, so it does matter. If you don't beleive me, try shooting a 12 gauge heavy field load with the shotgun held a couple of inches from your shoulder--that will really sharpen up the recoil. Ouchie! scot 21:25, 2 October 2006 (UTC)

Feel free to add to the list. scot 18:13, 2 October 2006 (UTC)

I am the author of the only book ever writen on kinetic energy. The title is Terminal Performance. You can down load or buy a soft cover addition fromm LuLu.com

The velocity of a gun under recoil is as you have stated "A 1 lb. pistol recoiling at 10 f/s is going to disturb the shooter much less than a 10 lb. rifle recoiling at 10 f/s." Momentum is equal to velocity. Recoil is equal energy. To figure the recoil energy of a firearm a person can use the momentum equation to calculate the velocity of that firearm. However the energy imparted to the shooter is calculated by mass times velocity squared or foot-pound force.

You are correct, a 1 lb. pistol recoiling at 10 f/s is going to disturb the shooter much less than a 10 lb. rifle recoiling at 10 f/s. But my question is this: how many foot-pounds force dose the 1 lb. pistol create and how many foot-pounds force dose the 10 lb. rifle create?

Feel free to continue this discussion here or IM greg_glover12@yahoo.com

Greg Glover 2:50 2 OCT 06 (PDT)

"The map is not the territory." I think the issue here is that we're talking about different things. I'm talking about the concept of recoil--recoil is the reaction of any device that launches a projectile, and recoil is the result of conservation of momentum. You are talking about measurements of recoil; you can measure recoil in terms of kinetic energy, momentum, or some improviced measurement like the aforementioned "Marcus inch". Now, if we're concerned about how the object upon which the recoil acts will deal with that, then we need to pick the appropriate measurement. If the gun is mounted solidly, say to a tank, then the question is how many pounds of force will be applied to the mounting brackets, and is that within the acceptable load? If the gun is mounted to a spring, as in a recoil operated firearm, then the question is how fast will the slide be moving, and is that slide velocity within the acceptable range for correct operation? If we have a gun on a hydraulic recoil cylinder, then the question might be how much heat will be generated by the agitation of the hydraulic fluid? When we're dealing with a person, then we're in the realm of felt recoil, and "sharp" and "soft" recoil start to have an impact, and measurement becomes a subjective combination of velocity, mass, and duration of the impulse.

Internal ballistics is based on Greenhills formula which is proportional to the cube; volume. Hydraulics is based on the square; area. You are mixing apples and oranges again.

I am sorry sir recoil is about energy and the soft or sharp recoil you are talking about was started by Col. Arthur Alphin of A-Square “Any Shot You Want” copywrite 1996. This is junk science. Buy my book and you will learn everything. My book has many reference for you to check.

Does that explanation make sense? If so, then lets see if we can use that as a guide for re-working the current contents of the article, and also laying the groundwork for some more expansion. scot 21:51, 2 October 2006 (UTC)

I believe you and I see recoil from two different perspectives. I see recoil from the prospective as a hunter and shoot that wants to understand what I feel and why. Also how it is a function of my firearm. I perceive your explanation of recoil as an explanation of what happens mechanically with a wide variety of mechanical devices. That would be either a heat engine its self or a device in conjunction with it to change the recoil.

I wish to collaborate with you on both our understandings of recoil. May be you can write the technical side of the mechanics of recoil and I can write the physical (Newtonian mechanics) side of recoil. Maybe there needs to be two different articles: Mechanical Recoil and Free Recoil. Greg Glover 2 OCT 06 3:52 (PDT)

I don't think a split is a good idea, I'm sure we can deal with everything needed in one article. Let's start by assembling a list of topics that we want to see covered in the article, and also a few definitions to make sure we're talking about the same things. Then we can haggle over definitions and arrange the topics into an outline. At that point we can divide the outline up and start writing, and then review each other's sections to come to a consensus. To keep things here neat, I'm starting a new section now...

Responce to the Above

As I promised. Here are the numbers and a bit of commentary.

To start with, check Wikipedia for Foot-pound force and check the references. All ballistics; internal, exterior and terminal are based on Sir Isaac Newton work. All calculations and definitions for energy are derived from Newton’s second law of motion F=ma including the greatest kinetic energy equation of them all: E=mc^{Superscript text}2

To respond to the article in Dillon Precision catalog. The 255gr. Bullet has a far lower perceived felt recoil then the 200gr. Bullet when fired from a .45ACP. Let us assuming the handgun is a M1911-A1 because we need a gun weight. I checked several reloading books to get an approximation of the powder charge for the same powder (Apples and Apples). Here are the numbers and why a 200gr. .45cal bullet has a greater perceived felt recoil.

200gr. At the at the muzzle is 1013fps and 456ft-lbf respectively for the bullet and 8.41ft-lbf for the 2.25lb handgun.

255gr. At the at the muzzle is 806fps and 366ft-lbf respectively for the bullet and 7.87ft-lbf for the 2.25lb handgun.

There are two separate equations for calculating bullet energy and recoil energy. Bullet weight or velocity is not directly connected to felt recoil. When all things are equal a the bullet that has the greatest amount of calculable transitional kinetic energy at the muzzle will recoil harder than a slower bullet. However when all things are not equal bullet weight or velocity is not an indicator of recoil energy; see the list below

It is Newton’s Second Law of motion that dictates this; F=ma

I believe you are writing about recoil as definition as a verb in the #1 (depending on dictionary)definition; the mechanics of recoil. I am writing about recoil as definition as a noun in the #3 (depending on dictionary) definition; Newtonian mechanics (physics). A definition specific to small arms.

Muzzle energy and Recoil calculations: 40gr. Bullet at 4000fps; 1421ft-lbf and 5.47ft-lbf respectively. 500gr. Bullet at 1100fps; 1344ft-lbf and 12.67ft-lbf respectively.

Recoil calculations: 6.75lb .45-70 T/C with a 500gr bullet at 1800fps equals 62ft-lbf 1lb pistol at 10fps equals 2ft-lbf 10lb rifle at 10fps equals 16ft-lbf 2.25lb handgun chambered in .38 Special equals 3.05ft-lbf 2.25lb handgun chambered in .221 Rem. Fireball equals 9.24ft-lbf 6.75lb 12ga. Shotgun chambered in Heavy Field load equals 46ft-lbf

Greg Glover16:17, 3 October 2006 (UTC)

Rewrite proposal

Here are the topics I listed above, plus the existing article topics, in a possible outline:

• Definition of recoil
• Recoil vs. energy (probably change to "momentum vs. energy")
  • Recoil is the reaction, and is a function of momentum
  • Ways to quantify recoil
  • Recoil energy can be calculated if the firearm mass is known
• Perception of recoil
  • Psychological effects
  • Controllability
  • "sharp" or "snappy" recoil vs. "soft" recoil
  • Bore axis and torque
• Recoil in mounted guns
  • Rigid vs. soft mounts
• Controlling recoil
  • Tie in muzzle brakes, along with examples above of powder/bullet masses.
  • Shotgun recoil absorbing stocks
  • Recoil absorbing materials (sorbothane, neoprene)
• Myths

As for definitions and units: I think "recoil" should be defined as the phenomenon that results from conservation of momentum when a projectile is launched. Since recoil is a function of momentum, I think that if we're going to pick a unit for "recoil", it should be mass times velocity. "Free recoil" is a measure of the recoil of a particular firearm/cartridge combination. This can be, and most often is, expressed as kinetic energy, or mass times velocity squared, with velocity being the velocity the firearm would reach if hung from string and fired.

As for perception issues: I think the difference between "soft" and "sharp" recoil, for two loads with the same free recoil energy from the same firearm, has to do with acceleration. A light, fast bullet will accelerate the gun faster than a heavy, slow bullet, and this means that the sharp load will accelerate the gun to a higher percentage of the free recoil velocity before the shooter's body starts to slow it down (since people are squishy, it's going to have room to accelerate). A soft load accelerates slower, and therefore will have compressed the shooter's body before it reaches such a high velocity, and will therefore won't reach as high a percentage of the free recoil velocity. Because of this, neither momentum nor energy is sufficient to quantify a shooter's perception of recoil, but the duration of the acceleration has to factor in there as well. scot 15:00, 3 October 2006 (UTC)