Resonances in scattering from potentials

In quantum mechanics, resonance cross section occurs in the context of quantum scattering theory, Which deals with studying the scattering of quantum particles from potentials. The scattering problem deals with the calculation of flux distribution of scattered particles/waves as a function of the potential, and of the state (characterized by conservation of momentum/energy) of the incident particle. For a free quantum particle incident on the potential, the plane wave solution to the time-independent Schrödinger wave equation is:

$\psi ({\vec {r}})=e^{i({\vec {k}}\cdot {\vec {r}})}$

For one-dimensional problems, The transmission coefficient $T$ is of interest. It is defined as:

$T={\frac {|{\vec {J}}_{\mathrm {trans} }|}{|{\vec {J}}_{\mathrm {inc} }|}}$

where ${\vec {J}}$ is the probability current density. This gives the fraction of incident beam of particles that makes it through the potential. For three-dimensional problems, we calculate the scattering cross-section $\sigma$, which, roughly speaking, is the total area of the incident beam which is scattered. Another quantity of relevance is the partial cross-section, $\sigma _{\text{l}}$, which denotes the scattering cross section for a partial wave of a definite angular momentum instigate. These quantities naturally depend on ${\vec {k}}$, the wave-vector of the incident wave, which is related to its energy by:

$E={\frac {\hbar ^{2}|{\vec {k}}|^{2}}{2m}}$

The values of these quantities of interest, the transmission coefficient $T$ (in case of one dimensional potentials), and the partial cross-section $\sigma _{\text{l}}$ show peaks in their variation with the incident energy $E$. These phenomena are called resonances.

One-dimensional case

Mathematical description

A one-dimensional finite square potential is given by

$V(x)={\begin{cases}V_{0},&0<x<L,\\0,&{\text{otherwise,}}\end{cases}},$

The sign of $V_{0}$ determines whether the square potential is a well or a barrier. To study the phenomena of resonance, we solve for a stationary state with energy $E>V_{0}$. The solution to the time-independent Schrödinger equation:

$-{\frac {\hbar ^{2}}{2m}}{\frac {d^{2}\psi }{dx^{2}}}+V(x)\psi =E\psi$

for the three regions $x<0,0<x<L,x>L$ are

$\psi _{1}(x)={\begin{cases}A_{1}e^{ik_{1}x}+B_{1}e^{-ik_{1}x},&x<0,\\A_{2}e^{ik_{2}x}+B_{2}e^{-ik_{2}x},&0<x<L,\\A_{3}e^{ik_{1}x}+B_{3}e^{-ik_{1}x},&x>L,\end{cases}}$

Here, $k_{1}$ and $k_{2}$ are the wave numbers in the potential-free region and within the potential respectively:

$k_{1}={\frac {\sqrt {2mE}}{\hbar }},$

$k_{2}={\frac {\sqrt {2m(E-V_{0})}}{\hbar }},$

To calculate $T$, we set $B_{3}=0$, which corresponds to the fact that there is no wave incident on the potential from the right. Imposing the condition that the wave function $\psi (x)$ and its derivative ${\frac {d\psi }{dx}}$ should be continuous at $x=0$ and $x=L$, we find relations between the coefficients, which allows us to find $T$ as

$T={\frac {|A_{3}|^{2}}{|A_{1}|^{2}}}={\frac {4E(E-V_{0})}{4E(E-V_{0})+V_{0}^{2}\sin ^{2}\left[{\sqrt {2m(E-V_{0})}}{\frac {L}{\hbar }}\right]}}$

It follows that the transmission coefficient $T$ reaches its maximum value of 1, when:

$\sin ^{2}\left[{\sqrt {2m(E-V_{0})}}{\frac {L}{\hbar }}\right]=0{\text{,or }}k_{2}={\frac {n\pi }{L}}$.

This is the resonance condition, which leads to the peaking of $T$ to its maxima, called resonance.

Physical picture (Standing de Broglie Waves and the Fabry-Pérot Etalon)

From the above expression, resonance occurs when the distance covered by the particle in traversing the well and back ($2L$) is an integral multiple of the De Broglie wavelength of a particle inside the potential ($\lambda ={\frac {2\pi }{k}}$). For $E>V_{0}$, reflections at potential discontinuities are not accompanied by any phase change. Therefore, resonances correspond to the formation of standing waves within the potential barrier/well. At resonance, the waves incident on the potential at $x=0$ and the waves reflecting between the walls of the potential are in phase, and reinforce each other. Far from resonances, standing waves can't be formed. Then, waves reflecting between both walls of the potential (at $x=0$ and $x=L$) and the wave transmitted through $x=0$ are out of phase, and destroy each other by interference. The physics is similar to that of transmission in Fabry–Pérot interferometer in optics, where the resonance condition and functional form of the transmission coefficient are the same.

A Plot Of Transmission co-efficient against (E/V₀) for shape factor of 30

A Plot Of Transmission co-efficient against (E/V₀) for shape factor of 13

Nature of resonance curves

As a function of the length of square well ($L$), the Transmission coefficient swings between its maximum of 1 and minimum of $\left[1+{\frac {V_{0}^{2}}{4E(E-V_{0})}}\right]^{-1}$, with a period of ${\frac {\pi }{k_{2}}}$. As a function of energy, the first term in the denominator dominates the oscillating term for $E>>V_{0}$ and therefore, $T\rightarrow 1$. Sharper resonances occur at lower energies, where the oscillating term in the denominator controls the behavior of $T$. The resonances become flat at higher energies, because the minima of $T$ get higher with $E$ as the effect of the oscillatory term in the denominator diminishes. This is demonstrated in plots of Transmission coefficient against incident particle energy for fixed values of the shape factor, defined as ${\sqrt {\frac {2mV_{0}L^{2}}{\hbar ^{2}}}}$

References

• Merzbacher Eugene. Quantum Mechanics. John Wiley and Sons.
• Cohen-Tannoudji Claude. Quantum Mechanics. Wiley-VCH.